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c++ - PortAudio 回调中的求和波

转载 作者:行者123 更新时间:2023-11-28 00:02:22 41 4
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我正在使用 PortAudio 开发声音应用程序。我有一个结构数组,表示传递到主回调函数的各个振荡器的数据。

当我尝试在一条线上将两个波相加并播放时,它起作用了,但是当我尝试使用 for 循环来做到这一点时,我可以任意对振荡器求和,但它不起作用。

所以这是可行的:

*out = sinetable[(int)oscs[0].phase % TABLE_SIZE] * (oscs[0].amp/2) + sinetable[(int)oscs[1].phase % TABLE_SIZE] * (oscs[1].amp/2);

但这不是:

for(int j = 0; j < 2; j++ )
{
*out += sinetable[(int)oscs[j].phase % TABLE_SIZE] * (oscs[j].amp / 2);
}

我只需要一种方法来对任意数量的振荡器求和。我认为这两种方法等效,但显然它们不是。

非常感谢任何帮助。

编辑:完整代码在这里:

         #include <stdio.h>
#include <math.h>
#include "portaudio.h"

#define NUM_SECONDS (2)
#define SAMPLE_RATE (44100)
#define FRAMES_PER_BUFFER (0) // PA will select in it's own..

#ifndef M_PI
#define M_PI (3.14159265)
#endif

#define TABLE_SIZE (4096) // < Hz / (sampling rate / table size ) [line 53]]
float sinetable[TABLE_SIZE];

typedef struct
{
float phase = 0;
float freq = 300;
float amp = 0.5;
}
Osc;

void initTable(){
for(int i = 0; i < TABLE_SIZE; i++){

sinetable[i] = sin(2 * M_PI * i/TABLE_SIZE);
}
}

/* This routine will be called by the PortAudio engine when audio is needed.
** It may called at interrupt level on some machines so don't do anything
** that could mess up the system like calling malloc() or free().
*/
static int patestCallback( const void *inputBuffer, void *outputBuffer,
unsigned long framesPerBuffer,
const PaStreamCallbackTimeInfo* timeInfo,
PaStreamCallbackFlags statusFlags,
void *userData )
{
Osc *oscs = (Osc*)userData;
float *out = (float*)outputBuffer;
unsigned long i;

(void) timeInfo; /* Prevent unused variable warnings. */
(void) statusFlags;
(void) inputBuffer;


for( i=0; i<framesPerBuffer; i++ )
{

/*
for(int j = 0; j < 2; j++ ){ //this won't work...
*out += sinetable[(int)oscs[j].phase % TABLE_SIZE] * (oscs[j].amp / 2);
}
*/
// but this does:
*out = sinetable[(int)oscs[0].phase % TABLE_SIZE] * (oscs[0].amp / 2) + sinetable[(int)oscs[1].phase % TABLE_SIZE] * ( oscs[1].amp / 2);

oscs[0].phase += oscs[0].freq / ( SAMPLE_RATE/(float)TABLE_SIZE );
oscs[1].phase += oscs[1].freq / ( SAMPLE_RATE/(float)TABLE_SIZE );

*out++;
}

return paContinue;
}



/*
* This routine is called by portaudio when playback is done.
*/
static void StreamFinished( void* userData )
{
Osc *oscs = (Osc *) userData;
// printf( "Stream Completed: %s\n", oscs->message );
}

/*******************************************************************/
int main(void);
int main(void)
{
PaStreamParameters outputParameters;
PaStream *stream;
PaError err;
Osc oscs[5];
int i;
oscs[1].freq = 400; oscs[2].freq = 500; oscs[3].freq = 600; oscs[4].freq = 700;

printf("PortAudio Test: output sine wave. SR = %d, BufSize = %d\n", SAMPLE_RATE, FRAMES_PER_BUFFER);

/* initialise sinusoidal wavetable */
for( i=0; i<TABLE_SIZE; i++ )
{
sinetable[i] = 2* M_PI * (i / TABLE_SIZE ); //using this global table
}
// oscs.phase = 0;

initTable();

err = Pa_Initialize();
if( err != paNoError ) goto error;

outputParameters.device = Pa_GetDefaultOutputDevice(); /* default output device */
if (outputParameters.device == paNoDevice) {
fprintf(stderr,"Error: No default output device.\n");
goto error;
}
outputParameters.channelCount = 1; /* mono output */
outputParameters.sampleFormat = paFloat32; /* 32 bit floating point output */
outputParameters.suggestedLatency = Pa_GetDeviceInfo( outputParameters.device )->defaultLowOutputLatency;
outputParameters.hostApiSpecificStreamInfo = NULL;

err = Pa_OpenStream(
&stream,
NULL, /* no input */
&outputParameters,
SAMPLE_RATE,
FRAMES_PER_BUFFER,
paClipOff, /* we won't output out of range samples so don't bother clipping them */
patestCallback,
&oscs );
if( err != paNoError ) goto error;

// sprintf( oscs.message, "No Message" );
err = Pa_SetStreamFinishedCallback( stream, &StreamFinished );
if( err != paNoError ) goto error;

err = Pa_StartStream( stream );
if( err != paNoError ) goto error;

printf("Play for %d seconds.\n", NUM_SECONDS );
Pa_Sleep( NUM_SECONDS * 1000 );

err = Pa_StopStream( stream );
if( err != paNoError ) goto error;

err = Pa_CloseStream( stream );
if( err != paNoError ) goto error;

Pa_Terminate();
printf("Test finished.\n");

return err;
error:
Pa_Terminate();
fprintf( stderr, "An error occured while using the portaudio stream\n" );
fprintf( stderr, "Error number: %d\n", err );
fprintf( stderr, "Error message: %s\n", Pa_GetErrorText( err ) );
return err;
}

最佳答案

我可以建议在求和之前将 *out 归零吗?

*out = 0;
for(int j = 0; j < 2; j++ )
{
*out += sinetable[(int)oscs[j].phase % TABLE_SIZE] * (oscs[j].amp / 2);
}

否则,由于 +=out 中的任何内容都会在总和中结束。

*out = sinetable[(int)oscs[0].phase % TABLE_SIZE] * (oscs[0].amp / 2) +  
sinetable[(int)oscs[1].phase % TABLE_SIZE] * (oscs[1].amp / 2);

解决这个问题是因为 = 覆盖了 out 中的任何内容。

关于c++ - PortAudio 回调中的求和波,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37847854/

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