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c++ - 在抛出 'std::system_error' 线程池实例后调用终止

转载 作者:行者123 更新时间:2023-11-27 23:54:29 26 4
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当我运行我的代码时:

nb workers = 12
I'm i : 0
HELLO I'm func1
BYE I'm func2
terminate called after throwing an instance of 'std::system_error'
what(): Invalid argument
Aborted (core dumped)

terminate called after throwing an instance of 'std::system_error'l

what(): Invalid argument

#ifndef CPP_PLAZZA_EXAMPLE_H
#define CPP_PLAZZA_EXAMPLE_H

#include <thread>
#include <vector>
#include <list>
#include <memory>
#include <functional>
#include <mutex>
#include <condition_variable>
#include <atomic>
#include <iterator>
#include <tuple>

class ThreadPool
{
public:
ThreadPool(size_t numThreads);
virtual ~ThreadPool();
void executeJob(std::function<void()> job, std::function<void()> notificationJob);
void wait_for_done();
private:
void loop();
std::pair<std::function<void()>, std::function<void()> > getNextJob();
std::vector<std::thread> m_workers;
std::list<std::pair<std::function<void()>, std::function<void()> > > m_jobs;
std::mutex m_lockJobsList;
std::condition_variable m_notifyJob;
std::atomic<bool> m_bTerminate;
class Terminated: public std::runtime_error
{
public:
Terminated(const std::string& what): std::runtime_error(what) {}
};

};

#endif //CPP_PLAZZA_EXAMPLE_H

这是我的.cpp

#include <iostream>
#include "example.h"


ThreadPool::ThreadPool(size_t numThreads):
m_workers(numThreads), m_bTerminate(false) {
m_workers.reserve(numThreads);
for (size_t i = 0; i < numThreads; i++) {
this->m_workers.emplace_back(&ThreadPool::loop, this);
}
/*for (std::vector<std::thread>::iterator it = this->m_workers.begin(); it != this->m_workers.end(); it++)
assert(std::next(it, 1) ==);*/
}

ThreadPool::~ThreadPool() {
{
std::unique_lock<std::mutex> lockList(m_lockJobsList);
m_bTerminate = true;
m_notifyJob.notify_all();
}

/* for(std::vector<std::thread>::iterator it = m_workers.begin(); it != m_workers.end(); it++) {
it->join();
}*/
std::this_thread::sleep_for(std::chrono::seconds(5));
}

void ThreadPool::executeJob(std::function<void()> job, std::function<void()> notificationJob) {
std::unique_lock<std::mutex> lockList(m_lockJobsList);
m_jobs.emplace_back(std::pair<std::function<void()>, std::function<void()> >(std::move(job), std::move(notificationJob)));
std::cout << m_jobs.size() << std::endl;
m_notifyJob.notify_one();
}

std::pair<std::function<void()>, std::function<void()> > ThreadPool::getNextJob() {
std::unique_lock<std::mutex> lockList(m_lockJobsList);

while(!m_bTerminate)
{
if(!m_jobs.empty())
{
std::pair<std::function<void()>, std::function<void()>> job = std::ref(m_jobs.front());
m_jobs.pop_front();
return job;
}

m_notifyJob.wait(lockList);
}

throw Terminated("Thread terminated");
}

void func1() {
std::cout << "HELLO I'm func1" << std::endl;

}

void ThreadPool::loop()
{
try
{
for(;;)
{
std::pair<std::function<void()>, std::function<void()> > job = getNextJob();
job.first();
job.second();
}
}
catch(Terminated& e)
{
}
}



void func2() {
std::cout << "BYE I'm func2" << std::endl;

}

void ThreadPool::wait_for_done()
{
std::cout << "nb workers = " << this->m_workers.size() << std::endl;
int i = 0;
for(std::vector<std::thread>::iterator it = m_workers.begin(); it != m_workers.end(); ++it) {
std::cout << "je suis i : " << i << std::endl;
i++;

(*it).join();
}
}

int main()
{
ThreadPool pool(6);

pool.executeJob(func1, func2);
pool.wait_for_done();
}

我认为我的错误是我在一个线程上多次加入,但如何解决?

编译行:

g++ -Wall -Werror -W -Wextra example.cpp -pthread -std=c++11

我在像这样加入之前尝试加入(等待完成):

for(std::vector<std::thread>::iterator it = m_workers.begin(); it != m_workers.end(); ++it) {
if ((*it).joinable())
(*it).join();
}

我有一个无限循环

最佳答案

你的 m_lockJobsList互斥量(和 m_notifyJob condvar)在 m_workers 之前被销毁在 ThreadPool 的 condvar 通知后唤醒时尝试锁定它的线程析构函数。

关于c++ - 在抛出 'std::system_error' 线程池实例后调用终止,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43684218/

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