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c++ - 通过多线程判断每个字符在一个文件中出现了多少次

转载 作者:行者123 更新时间:2023-11-27 23:48:52 24 4
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我的代码。我写了我可以。现在需要你的帮助。告诉我怎么了。我如何屏蔽尽可能多的符号?我不知道如何正确地做,我看书。但仍然没有解决

void TextThread(std::string str)
{
std::ifstream text(str);
if (!text)
std::cout << "No open file" << "\n";

std::istream_iterator<char> input(text);
std::istream_iterator<char> output;

std::vector<char> symvol(input, output);

unsigned maxThreadCount = std::thread::hardware_concurrency();
const std::size_t minLength = symvol.size() / maxThreadCount;
const std::size_t modulo = symvol.size() % maxThreadCount;

std::vector<std::size_t> results;
results.reserve(maxThreadCount);

std::vector<std::thread> threads;
threads.reserve(maxThreadCount - 1);

for (std::size_t i = 0; i < modulo; ++i)
results.emplace_back(minLength + 1);

if (minLength > 0)
{
for (std::size_t i = modulo; i < maxThreadCount; ++i)
results.emplace_back(minLength);
}
for (std::size_t i = 1; i < threads.size(); ++i)
threads.emplace_back(threads[i - 1] + 1, threads[i - 1] + threads[i]);

std::for_each(threads.begin(), threads.end(),
std::mem_fn(&std::thread::join));


for (unsigned int i = 0; i < symvol.size(); ++i)
std::cout << symvol[i] << "\n";
}


int main()
{
TextThread("D:\\text.txt");
return 0;
}

更新:我会在屏幕上显示所有字符

void TextThread(std::string str)
{
std::ifstream text(str);
if (!text)
std::cout << "No open file" << "\n";

std::istream_iterator<char> input(text);
std::istream_iterator<char> output;

std::vector<char> symvol(input, output);
for (unsigned int i = 0; i < symvol.size(); ++i)
std::cout << symvol[i] << "\n";
}

UPD2:

像你一样做。它仍然与多线程有关

 using Symbol = std::array<size_t, 256>;
Symbol CountSymbol(std::vector<char> const& data)
{
Symbol countSymbol{};
for (unsigned char ch : data)
countSymbol[ch] += 1;
return countSymbol;
}


Symbol SymbolFile(std::string const& fname)
{
std::ifstream text(fname);

if (!text)
throw std::runtime_error("No open file");

std::vector<char> const data(std::istreambuf_iterator<char>{text}, {});
return CountSymbol(data);
}

int main()
{
Symbol symbol = SymbolFile("D:\\text.txt");
for (int ch = 0; ch <= 255; ++ch)
{
if (symbol[ch])
{
if (std::isprint(ch))
std::cout << "Character '" << char(ch) << "' occurs " <<
symbol[ch] << " times\n";
else
std::cout << "Character #" << ch << " occurs " << symbol[ch]
<< " times\n";
}
}
}

UPD3

 #include "stdafx.h"
#include <iostream>
#include <fstream>
#include <iterator>
#include <algorithm>
#include <string>
#include <vector>
#include <unordered_map>
#include <thread>
#include <cctype>
#include <clocale>
#include <numeric>

std::vector<std::pair<std::size_t, std::size_t>> GenerateIntervals(const
std::vector<char>& text)
{
std::size_t maxThreadCount = std::thread::hardware_concurrency();
const std::size_t minLength = text.size() / maxThreadCount;
const std::size_t modulo = text.size() % maxThreadCount;

std::vector<std::size_t> intervalLengthPerThread;
intervalLengthPerThread.reserve(maxThreadCount);

for (std::size_t i = 0; i < modulo; ++i)
intervalLengthPerThread.emplace_back(minLength + 1);

if (minLength > 0)
{
for (std::size_t i = modulo; i < maxThreadCount; ++i)
intervalLengthPerThread.emplace_back(minLength);
}

std::vector<std::pair<std::size_t, std::size_t>> intervals;
intervals.reserve(intervalLengthPerThread.size());

intervals.emplace_back(0, 0 + intervalLengthPerThread[0] - 1);
for (std::size_t i = 1; i < intervalLengthPerThread.size(); ++i)
intervals.emplace_back(intervals[i - 1].second + 1, intervals[i - 1].second + intervalLengthPerThread[i]);

return intervals;
}

void BuildHistogram(const std::pair<std::size_t, std::size_t>& textRange,
const std::vector<char>& text, std::unordered_map<char, std::size_t>&
histogram)
{
for (std::size_t i = textRange.first; i < textRange.second; ++i)
++histogram[text[i]];
}

std::vector<char> ReadDataFromFile(const std::string& pathToFile)
{
std::ifstream stream(pathToFile);

if (!stream)
{
std::vector<char> result;
std::cout << "Can not open file" << "\n";
return result;
}

std::istream_iterator<char> it(stream);
std::istream_iterator<char> itEnd;

std::vector<char> text(it, itEnd);
}

int main()
{
auto text = ReadDataFromFile("D:\\text.txt");

const auto textIntervals = GenerateIntervals(text);
const auto usedThreadCount = textIntervals.size();

std::vector<std::unordered_map<char, size_t>> histograms(usedThreadCount);
std::vector<std::thread> threads(usedThreadCount);

for (std::size_t i = 0; i < usedThreadCount; ++i)
threads[i] = std::thread(BuildHistogram, std::cref(textIntervals[i]), text, std::ref(histograms[i]));

for (std::size_t i = 0; i < usedThreadCount; ++i)
threads[i].join();

std::unordered_map<char, size_t> histogram;
for (const auto& hist : histograms)
{
for (const auto& pair : hist)
histogram[pair.first] += pair.second;
}

for (int ch = 0; ch < 256; ++ch)
{
if (text[ch])
{
std::cout << "Character '" << char(ch) << "' occurs " << text[ch] << " times\n";
}
}
return 0;

最佳答案

我会在这里提供帮助,因为你迷路了。

目标

认为你想要一个直方图,比如:

std::array<size_t, 256> histo;

这里,每个元素对应输入字符的整数值(比如a是97)。

下面是简单的实现:

using Histo = std::array<size_t, 256>;

Histo histogram(std::vector<char> const& data) {
Histo histo {}; // value initialize, makes sure all elements are 0

for (auto ch : data) {
histo[ch] += 1;
}

return histo;
}

Note There's a very subtle thing here where I convert the character to unsigned char (could also say uint8_t). This is because some platforms will have char be signed and that leads to errors when indexing histo[ch] or when comparing (e.g. ch <= 255 would always be true).

您可以像这样对文件的内容进行操作:

Histo histogram_file(std::string const& fname) {
std::ifstream text(fname);

if (!text)
throw std::runtime_error("No open file");

std::vector<char> const data(std::istreambuf_iterator<char>{text}, {});
return histogram(data);
}

Note The use of istreambuf_iterator does not skip whitespace (as istreambuf_iterator does by default, see http://en.cppreference.com/w/cpp/io/manip/skipws).

现场演示

简单代码 Live On Coliru

#include <thread>
#include <vector>
#include <string>
#include <fstream>
#include <iostream>
#include <iterator>

using Histo = std::array<size_t, 256>;

Histo histogram(std::vector<char> const& data) {
Histo histo {}; // value initialize, makes sure all elements are 0

for (unsigned char ch : data) {
histo[ch] += 1;
}

return histo;
}


Histo histogram_file(std::string const& fname) {
std::ifstream text(fname);

if (!text)
throw std::runtime_error("No open file");

std::vector<char> const data(std::istreambuf_iterator<char>{text}, {});
return histogram(data);
}

int main() {
Histo histo = histogram_file("main.cpp");
for (int ch = 0; ch <= 255; ++ch) {
if (histo[ch]) {
if (std::isprint(ch))
std::cout << "Character '" << char(ch) << "' occurs " << histo[ch] << " times\n";
else
std::cout << "Character #" << ch << " occurs " << histo[ch] << " times\n";
}
}
}

打印类似的东西

Character #10 occurs 41 times
Character ' ' occurs 224 times
Character '!' occurs 1 times
Character '"' occurs 16 times
Character '#' occurs 7 times
...
Character 'x' occurs 3 times
Character 'y' occurs 1 times
Character 'z' occurs 2 times
Character '{' occurs 9 times
Character '}' occurs 9 times

使其线程化

要分发工作,我们必须调用 histogram对于 vector 数据的一部分。让我们稍微修改我们的函数来实现这一点:

template <typename Iterator> // could just use `char const*` but let's not
Histo histogram(Iterator begin, Iterator end) {
Histo histo {}; // value initialize, makes sure all elements are 0

for (auto it = begin; it != end; ++it) {
histo[*it] += 1;
}

return histo;
}

Histo histogram(std::vector<char> const& data) {
return histogram(data.begin(), data.end());
}

如您所见,我们可以将“旧”签名直接转发到新的、更灵活的界面。当然你可以对 char const* 挑剔。直接并具有完全相同的代码,但如果输入与 vector 有任何不同,它就无法正常工作。或者如果它变成了 std::deque<unsigned char>等等

并发

我们希望将工作分成相等的 block :

using It = std::vector<char>::const_iterator;

// calculate chunk size
auto chunk = data.size() / num_threads;
if (chunk*num_threads < data.size()) chunk += 1;

Note that the last chunk could be extend (

因为你不能(有用地)分享 Histo所有线程之间的对象(同步访问的成本将远远超过并发处理的任何速度优势),我们必须有 Histo每个线程。

让我们先笨拙地手动操作:

////////////////////////////////////////////
// start chunk threads
struct worker_t {
Histo local; // histogram per thread
std::thread th;

void run(It begin, It end) {
local = histogram(begin, end);
}
};
std::vector<worker_t> workers(num_threads);

现在我们可以开始了 run在每个工作实例上,传递计算的子范围:

int i = 0;
for (auto& w : workers) {
auto begin = data.begin()+chunk*i,
end = std::min(begin + chunk, data.end());
w.th = std::thread(&worker_t::run, std::ref(w), begin, end);
++i;
}

等待与合并

////////////////////////////////////////////
// wait for completion
for (auto& w : workers) {
if (w.th.joinable())
w.th.join();
};

这几乎是您已经拥有的。

////////////////////////////////////////////
// merge results
Histo histo;
for (auto& w : workers) {
merge_into(histo, w.local);
}

return histo;

注意编写你想阅读的代码,然后再实现更多细节的习惯。在这种情况下,我们仍然定义了 merge_into :

void merge_into(Histo& into, Histo const& part) {
for (auto& p : part)
into[p.first] += p.second;
}

体力劳动者演示

以上 Live On Coliru MSVC on RexTester

#include <thread>
#include <vector>
#include <string>
#include <fstream>
#include <iostream>
#include <iterator>
#include <map>

using Histo = std::map<char, size_t>;

void merge_into(Histo& into, Histo const& part) {
for (auto& p : part)
into[p.first] += p.second;
}

template <typename Iterator> // could just use `char const*` but let's not
Histo histogram(Iterator begin, Iterator end) {
Histo histo {}; // value initialize, makes sure all elements are 0

for (auto it = begin; it != end; ++it) {
histo[*it] += 1;
}

return histo;
}

Histo histogram(std::vector<char> const& data) {
return histogram(data.begin(), data.end());
}

Histo parallel_histo(std::vector<char> const& data, size_t num_threads = std::thread::hardware_concurrency()) {
using It = std::vector<char>::const_iterator;

// calculate chunk size
auto chunk = data.size() / num_threads;
if (chunk*num_threads < data.size()) chunk += 1;

////////////////////////////////////////////
// start chunk threads
struct worker_t {
Histo local; // histogram per thread
std::thread th;

void run(It begin, It end) {
local = histogram(begin, end);
}
};
std::vector<worker_t> workers(num_threads);

int i = 0;
for (auto& w : workers) {
auto begin = data.begin()+chunk*i,
end = std::min(begin + chunk, data.end());
w.th = std::thread(&worker_t::run, std::ref(w), begin, end);
++i;
}

////////////////////////////////////////////
// wait for completion
for (auto& w : workers) {
if (w.th.joinable())
w.th.join();
};

////////////////////////////////////////////
// merge results
Histo histo;
for (auto& w : workers) {
merge_into(histo, w.local);
}

return histo;
}

Histo histogram_file(std::string const& fname) {
std::ifstream text(fname);

if (!text)
throw std::runtime_error("No open file");

return parallel_histo({std::istreambuf_iterator<char>{text}, {}});
}

int main() {
Histo histo = histogram_file("main.cpp");
for (int ch = 0; ch <= 255; ++ch) {
if (histo[ch]) {
if (std::isprint(ch))
std::cout << "Character '" << char(ch) << "' occurs " << histo[ch] << " times\n";
else
std::cout << "Character #" << ch << " occurs " << histo[ch] << " times\n";
}
}
}

打印与之前相同的输出。

不那么笨拙

分配接受输入和生成结果的任务的“标准库”是使用 std::async它可以简单地返回结果。它并不完美,但工作量少得多:

Live On Coliru

Histo parallel_histo(std::vector<char> const& data, size_t num_threads = std::thread::hardware_concurrency()) {
// calculate chunk size
auto chunk = data.size() / num_threads;
if (chunk*num_threads < data.size()) chunk += 1;

////////////////////////////////////////////
// start tasks
std::vector<std::future<Histo> > tasks(num_threads);

int i = 0;
for (auto& t : tasks) {
auto begin = data.begin()+chunk*i,
end = std::min(begin + chunk, data.end());

t = std::async([=,&data] { return histogram(begin, end); });
}

Histo histo;
for (auto& t : tasks) {
merge_into(histo, t.get());
}

return histo;
}

禅师

当然,如果你真的了解标准库,你就会使用它(c++17):

#include <atomic>
#include <execution>
#include <algorithm>

using Histo = std::vector<std::atomic_size_t>;

Histo histogram(std::vector<char> const& data) {
Histo histo(256);
std::for_each(std::execution::par_unseq, data.begin(), data.end(), [&histo](unsigned char ch) { ++histo[ch]; });
return histo;
}

Histo histogram_file(std::string const& fname) {
std::ifstream text(fname);

if (!text)
throw std::runtime_error("No open file");

return histogram({std::istreambuf_iterator<char>{text}, {}});
}

遗憾的是您还不能使用它,因为没有编译器供应商实际(完全)实现它。

关于c++ - 通过多线程判断每个字符在一个文件中出现了多少次,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48316402/

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