c++ - 在 C++ 中寻找中间值

Question

我对代码的一部分感到困惑。首先，我试图找到 4 个给定数字(随机)的最小值和最大值。然后我需要找到中间数的平均值，这是我的代码，任何帮助将不胜感激，谢谢!

我想我应该使用我在第一部分中使用的最小和最大函数吗？但我不知道该怎么做

#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;

int result;

int min(int a, int b, int c, int d)
{
    result = a;
    if (b < result) result = b;
    if (c < result) result = c;
    if (d < result) result = d;
    return result;
}

int max(int a, int b, int c, int d)
{
    int result = a; 
    if (b > result) result = b;
    if (c > result) result = c;
    if (d > result) result = d;
    return result;
}

int main()
{
    int Min,Max;
    Min = min(2,6,3,4);
    cout << " The result for minimum is " << Min <<endl;
    Max = max(2,6,3,4);
    cout << " The result for maximum is " << Max;
}

/**
  Computes the average of the middle values of four given values
  (that is, without the largest and smallest value).
  Hint: Use the given min function. You may also want to define a
  max helper function or take advantage of the fact that max can be
  computed from the min of the negative values.
**/

/** things got confused after this...the first part is actually finished with the help from my other question **/

    int mv1;

double middle(int a, int b, int c, int d)
{
    int  mv1=a;
    if(a<=b)
        return a;
}

int main1()
{

    int x;
    int y;
    int z;
    int n;
    int md;

    cout << "Please enter a number: ";
    cin>>x;
    cout << "Enter another number:  ";
    cin>>y;
    cout << "Enter the third number:  ";
    cin>>z;
    cout << "Enter the fourth number:  ";
    cin>>n;

    md=middle(x,y,z,n);
    cout << endl<<"middle is "<<md <<endl;
    return 0;


}

Answer 1

你应该开始学习标准模板库，你可以这样做:

#include <vector>
#include <algorithm>
#include <iostream>

double median(int a, int b, int c, int d)
{
    std::vector<int> v{a,b,c,d};
    std::sort(v.begin(),v.end());
    return static_cast<double>(v[1]+v[2])/2;
}

int main() {
    std::cout << "median of 1,2,3,4: " << median(1,2,3,4) << "\n";
}

哪些输出:

middle of 1,2,3,4: 2.5

使用 STL 算法将使您的代码更具表现力且更易于理解。我建议你从头开始学习它们