gpt4 book ai didi

c++ - vector 迭代器不可取消引用( vector 内 vector )

转载 作者:行者123 更新时间:2023-11-27 23:25:03 28 4
gpt4 key购买 nike

我正在尝试将这些 vector 中的一些数据写入文本文件。当我运行代码时,它返回运行时错误。 CategoryProductCartCustomerAddress都是struct 包含每个 get_member 返回的成员。

ofstream write_cats;
write_cats.open("catprd.dat", ios::out, ios::trunc);
vector<Category>::iterator i;
write_cats << cats.size() << endl;
for (i = cats.begin(); i < cats.end(); i++) {
write_cats << i -> get_catid() << '\t';
}
vector<Product>::iterator j;
write_cats << prods.size() << endl;
for (j = prods.begin(); j < prods.end(); j++) {
write_cats << j -> get_prodid() << '\t';
write_cats << j -> get_prodprice() << endl;
}
write_cats.close();

ofstream write_carts;
write_carts.open("carts.dat", ios::out, ios::trunc);
vector<Cart>::iterator k;
write_carts << carts.size() << endl;
for (k = carts.begin(); k < carts.end(); k++) {
write_carts << k -> get_cartid() << '\t';
write_carts << k -> get_day() << endl;
}
vector<Cart_item>::iterator l;
write_carts << cart_items.size() << endl;
for (l = cart_items.begin(); l < cart_items.end(); l++) {
write_carts << l -> get_cartitemid() << '\t';
write_carts << l -> get_qty() << endl;
}
write_carts.close();

ofstream write_custs;
write_custs.open("custs.dat", ios::out, ios::trunc);
vector<Customer>::iterator m;
vector<Address>::iterator n;
write_custs << custs.size() << endl;
for (m = custs.begin(); m < custs.end(); m++) {
write_custs << m -> get_cust_id() << '\t';
write_custs << n -> get_zip_code() << endl;
}
write_custs.close();

返回运行时错误“Vector iterator not dereferencable”

下面是 struct Address 的样子:

using namespace std;
#pragma once
#include <string>

struct Address {

public:

int get_st_number() const{return st_number;}
int get_zip_code() const{return zip_code;}
string get_st_name() const{return st_name;}



Address(){}
Address (int num, string name, int zip)
: st_number(num), st_name(name), zip_code(zip) {}

private:
int st_number;
int zip_code;
string st_name;


};

构造客户:

struct Customer {
public:

Address get_address() const{return addr;}
int get_cust_id() const{return cust_id;} customer id
string get_name() const{return cust_name;}
Customer (int id, string n, Address a)
: cust_id(id), cust_name(n), addr(a) {}


string display_addr() const {
std::cout<<setw(15)<<cust_name<<" ";
std::cout<<setw(15)<<cust_id<<" ";

return string();
}



private:

int cust_id;
string cust_name;
Address addr;
};

最佳答案

你忘记初始化vector<Address>::iterator n;

关于c++ - vector 迭代器不可取消引用( vector 内 vector ),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10032161/

28 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com