c++ - 要求基类中的方法被其所有子类覆盖

Question

在 C++ 中，是否可以要求基类中的方法被其所有派生类覆盖而不使其成为纯虚方法？

#include <iostream>
using namespace std;

class BaseClass{
    public:
    int printStuff(){ //find some way to require all derived classes to override this method
        cout << "Printing some stuff";
    }
};

class DerivedClass: public BaseClass{

};

int main(){
    cout << "Hello World!";
    return 0;
}

Answer 1

我知道你说过你不想使用纯虚函数，但你可以使用纯虚函数并且仍然给方法一个定义，如果那是你想要做的(不确定你是否已经知道):

class BaseClass{
public:
    virtual int printStuff() = 0;
};

// give the pure virtual function an implementation
int BaseClass::printStuff() {
    cout << "Printing some stuff";
}

class DerivedClass: public BaseClass{
    // compiler error; DerivedClass must override printStuff
};

class DerivedClass2: public BaseClass{
public:
    int printStuff() {
        return BaseClass::printStuff(); // use the base class's implementation
    }
};