javascript - 使用 matchesQuery 并包含两次 parse.com javascript

Question

我使用了 include 和 matchesquery 两次，但在第二个 matchesquery 上，不接受该限制。例如，在我的代码中:

function findMe(){
var controller = Parse.Object.extend("Controller"); 
var controllerType = Parse.Object.extend("ControllerType"); 
var Type = Parse.Object.extend("TypeMagazia");
var CategoryMagazia = Parse.Object.extend("CategoryMagazia");   


    var queryControllerType = new Parse.Query(controllerType);
    var queryType = new Parse.Query(Type);          
    var queryCategoryMagazia = new Parse.Query(Type);   


    //start type 
    var typeTable = [];
      var cafebar = document.getElementById('cafe_bar');
      var club = document.getElementById('club');
      var restaurant = document.getElementById('restaurant');         
      var pistes = document.getElementById('pistes');
      //perasma value ston pinaka
      if(cafebar.checked){ typeTable.push(cafebar.value);}
      if(club.checked){ typeTable.push(club.value);}
      if(restaurant.checked){ typeTable.push(restaurant.value);}
      if(pistes.checked){ typeTable.push(pistes.value);}
      console.log(typeTable);

     //start category 
    var categoryTable = [];
    for( var i =0; i<5; i++){
    var cat = "cat"+i;
    console.log(cat);
      var category = document.getElementById(cat);
      //perasma value ston pinaka
      if(category.checked){ categoryTable.push(category.value);}
    }
     console.log(categoryTable);



    for (var i = 0; i<typeTable.length; i++){
for (var j = 0; j<categoryTable.length; j++){

                    queryControllerType.exists('objectId');

                    queryType.equalTo("TypeName", typeTable[i]);
                    queryCategoryMagazia.equalTo("CategoryName", categoryTable[j]);



                    queryControllerType.include('TypeMagaziaID');
                    queryControllerType.include('CategoryMagaziaID');                       

                    queryControllerType.matchesQuery('TypeMagaziaID', queryType);
                    queryControllerType.matchesQuery('CategoryMagaziaID', queryCategoryMagazia);

                    queryControllerType.ascending('objectId')
                    queryControllerType.find().then(function(results) {
                        console.log("results.length : "+results.length);

                         for (var k = 0; k < results.length; k++) {
                             var object = results[k];                       
                             var typeB = object.get('TypeMagaziaID');
                             var catB = object.get('CategoryMagaziaID');


                             var nameType = typeB.get("TypeName");  
                             var nameCategory = catB.get("CategoryName");

                             console.log(" Id : "+object.id +" typeName : "+nameType +" CategoryName : "+nameCategory);
                         }

                 });

                }
            }

运行代码后的结果是:

'结果.长度:0"

当我评论第二个匹配查询并选择参数“club”作为第一个匹配查询时

    queryControllerType.exists('objectId');

                    queryType.equalTo("TypeName", typeTable[i]);
                    queryCategoryMagazia.equalTo("CategoryName", categoryTable[j]);



                    queryControllerType.include('TypeMagaziaID');
                    queryControllerType.include('CategoryMagaziaID');                       

                    queryControllerType.matchesQuery('TypeMagaziaID', queryType);
                    //queryControllerType.matchesQuery('CategoryMagaziaID', queryCategoryMagazia);

                    queryControllerType.ascending('objectId')
                    queryControllerType.find().then(function(results) {
                        console.log("results.length : "+results.length);

                         for (var k = 0; k < results.length; k++) {
                             var object = results[k];                       
                             var typeB = object.get('TypeMagaziaID');
                             var catB = object.get('CategoryMagaziaID');


                             var nameType = typeB.get("TypeName");  
                             var nameCategory = catB.get("CategoryName");

                             console.log(" Id : "+object.id +" typeName : "+nameType +" CategoryName : "+nameCategory);
                         }

                 });

我正在获取这些结果:

results.length : 8 postMagaziaTypeCategory.php:400 Id : 8kl40HYG9J typeName : club CategoryName : bistro postMagaziaTypeCategory.php:400 Id : 91HGIQFRGj typeName : club CategoryName : disco postMagaziaTypeCategory.php:400 Id : Ddw6S8hl0Z typeName : club CategoryName : cockteil postMagaziaTypeCategory.php:400 Id : LtiIQXxOx6 typeName : club CategoryName : cockteil postMagaziaTypeCategory.php:400 Id : Yp6j0uJLL3 typeName : club CategoryName : bistro postMagaziaTypeCategory.php:400 Id : dMnMugrKfL typeName : club CategoryName : cockteil postMagaziaTypeCategory.php:400 Id : hCDeYHPLO3 typeName : club CategoryName : bistro postMagaziaTypeCategory.php:400 Id : ntrrKiNaFq typeName : club CategoryName : bistro

我想创建像图片上这样的东西:

Answer 1

也许是因为您没有正确查询categoryMagazia..

如果您仔细观察第一个代码块，您会尝试查询相同的 Type 两次。

如果你改变这些行

var queryControllerType = new Parse.Query(controllerType);
var queryType = new Parse.Query(Type);          
var queryCategoryMagazia = new Parse.Query(Type);  

至此

var queryControllerType = new Parse.Query(controllerType);
var queryType = new Parse.Query(Type);          
var queryCategoryMagazia = new Parse.Query(CategoryMagazia);  

我想你会没事的。

而且很高兴看到人们继续使用 Parse!

祝你编码愉快!