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Javascript 选择

转载 作者:行者123 更新时间:2023-11-27 23:11:59 28 4
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我有一个下拉列表“磅”、“克”、“千克”和“盎司”。我想要这样一种情况,当我选择 gram 来执行一个函数时,当我在输入字段中输入一个值时,当我选择 pounds 时,我想要另一个函数来执行时我在输入字段中输入一个值,依此类推。我已经尝试过了,但无法完成。

这是我的代码....

HTML

<div id="weight-dropdown">
<h4>Weight Converter</h4>
<select id="select-weight">
<option value="0">...</option>
<option value="1">Pounds</option>
<option value="2">Grams</option>
<option value="3">Kilograms</option>
<option value="4">Ounce</option>
</select>
<input id="input" type="number" placeholder="Enter value...">
</div> <!-- weight dropdown-->

<div id="output">
<div>
<h5>Pounds (lbs) :</h5>
<div id="poundsOutput"></div>
</div>

<div>
<h5>Grams (g) :</h5>
<div id="gramsOutput"></div>
</div>

<div>
<h5>Kilorams (kg) :</h5>
<div id="kgOutput"></div>
</div>

<div>
<h5>Ounce (oz) :</h5>
<div id="ozOutput"></div>
</div>
</div><!--output-->

Javascript

if (document.getElementById("select-weight").selectedIndex = "0"){
document.getElementById("input").addEventListener("input", function(e){
var pounds= e.target.value;
document.getElementById("poundsOutput").innerHTML = pounds
document.getElementById("gramsOutput").innerHTML = pounds/0.0022046;
document.getElementById("kgOutput").innerHTML = pounds/2.2046;
document.getElementById("ozOutput").innerHTML = pounds*16;

})
} else (document.getElementById("select-weight").selectedIndex = "2"){
document.getElementById("input").addEventListener("input", function(e){
var grams= e.target.value;
document.getElementById("poundsOutput").innerHTML = grams*0.0022046;
document.getElementById("gramsOutput").innerHTML = grams;
document.getElementById("kgOutput").innerHTML = grams/1000;
document.getElementById("ozOutput").innerHTML = grams/28.35;

})

最佳答案

您根据输入值分配输入监听器一次,但一旦分配,它就会总是被触发,即使选择发生变化。可以反过来做并使用开关:

  document.getElementById("input")
.addEventListener("input", function(e){
var input = e.target.value;
switch(document.getElementById("select-weight").selectedIndex){
case 0:
return alert("Please select unit");
break;
case 1 :
var pounds = input;
var grams = input/0.0022046;
var kg = input/2.2046;
var oz = input * 16;
break;
case 2:
var pounds = input * 0.0022046;
var grams = input;
var kg = pounds/2.2046;
var oz = pounds * 16;
break;
case 3:
//...
break;
}

//update DOM with values

document.getElementById("poundsOutput").innerHTML = pounds;
document.getElementById("gramsOutput").innerHTML = grams;
document.getElementById("kgOutput").innerHTML = kg;
document.getElementById("ozOutput").innerHTML = oz;

});

虽然上面的代码很好/可以理解,但您可以使用更短的方法。您可以通过除以某个数字来获得下一个“行”的值,通过乘以某个数字来获得前一个“行”的值。所以你可以这样做:

 var conversion = [
null,//an endpoint
1,// pounds / this = grams
2,//grams / this = kg
3, //kg/this = oz
null//an endpoint
];

//some pseudocode:
var index = selectWeight.selectedIndex;
var start = event.target.value;

var result = [];

//now multiple from right to left of selected index:
conversion.slice(0,index).reduceRight(function(value,multiplier,i){
result[i] = value;
return value * multiplier;
}, start);

//divide from right to left:

conversion.slice(index-1).reduce(function(value,divider,i){
result[index+i-1] = value;
return value / divider;
},start);

现在我们得到了结果:

var [pounds,grams,kg,oz] = result;

关于Javascript 选择,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45568209/

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