c++ - 对输入的名称 'age' 进行排序，然后显示结果

Question

我想按各个输入名称的升序对年龄进行排序，然后根据该列表显示列表。我设法对它们进行了排序，但我似乎无法根据年龄正确显示名称。

这是我的代码:-

#include <iostream>
using namespace std;

int main()
{
    char name [5][25];
    int age [5];
    int i;

    for (i=0 ; i<5 ; i++)
    {
        cout << "Enter name " << i+1 << "  :   ";
        cin >> name [i];
        cout << "Enter age     :   ";
        cin >> age [i];
        cout << endl;
    }

    cout << "\n********** Your entered data **********\n\n";

    cout << "\tName" << "\t\t" << "Age\n\n";

    for (i=0 ; i<5 ; i++)
    {
        cout << "\t" << name [i] << "\t\t" << age [i];
        cout << endl;
    }

    int hold;

    for (i=0 ; i<5 ; i++)
    {
        for (int j=0 ; j<5 ; j++)
        {
            if (age [j] > age [j+1])
            {
                hold = age [j];
                age [j] = age [j+1];
                age [j+1] = hold;
            }
        }
    }

    cout << "\n\n******* Sorted data (w.r.t age) *******\n\n";

    cout << "\tName" << "\t\t" << "Age\n\n";

    for (i=0 ; i<5 ; i++)
    {
        cout << "\t" << name [i] << "\t\t" << age [i];
        cout << endl;
    }

    return 0;
}

问题出在最后一个 for 循环上。你们谁能帮我实现这个逻辑？

Answer 1

改变你的交换逻辑。交换姓名和年龄。

    char holdstr[25]; ///Temporary string to swap.

if (age [j] > age [j+1] || (age[j] == age[j+1])
{
    //Swap the age and name both.
    hold = age [j];
    strcpy(holdstr, name[j]);

    age [j] = age [j+1];
    strcpy(name[j], name[j+1]);

    age [j+1] = hold;
    strcpy(name[j+1], holdstr);
}

您应该将 condition 包装在 if 中的函数中，以便您可以轻松更改逻辑。