c++ - 警告 634 : Strong type mismatch (type 'bool' ) in equality or conditional

Question

This is part of my code base 
I am rying to run the below code and getting the warning like below code:

    #define assert_always()         assert(TRUE)

    base::derived(
        uint8 id;
    ){
        switch(id)
        {
        case one:
        ----;
        break;
        case two:
        ----;
        break;
        default:
        assert_always();
        break;
        }
    }

    Warning 634: Strong type mismatch (type 'bool') in equality or conditional  .......

The line number is pointing to `assert_always()` function call. Can you guide me to first to understand and then solve this warning?

I have checked by changing TRUE to true but stil having the same problem ...

Actually code was like this in c++ :
#define assert_always()

    base::derived(
        uint8 id;
    ){
        switch(id)
        {
        case one:
        ----;
        break;
        case two:
        ----;
        break;
        default:
        assert_always();
        break;
        }
    }

I got the warning Warning 634: Strong type mismatch (type 'bool') in equality or conditional so I introduce  

定义 assert_always() 断言(TRUE)

但还是有警告，在其他回复后，修改为

定义 assert_always() 断言(真)

but still warning is there ...I am not getting all the exact reason behind this ...

----;行是一些功能......并且提到的代码是在 C++ 中

Answer 1

什么是TRUE？

用实际的 bool 常量试试:

#define assert_always assert(false)

另请注意，assert(true) 永远不会断言，因为表达式(字面上)为真。