c++ - 如何检查忽略其模板参数的类型

Question

如何在忽略其模板参数的情况下确定类类型。

所以对于完全指定的类型，如 MyClass<param1, param2, ...> , 我想检查它是否确实是 MyClass 类型？

本着

的精神

typedef ClassName<param1, param2, ...> T;

//Now my program receives T which can be any arbitrary type
//and I want to have something like the following
//check_if_MyClassType<T>::value should be true
//check_if_MyClassType<int>::value should be false
//check_if_MyClassType<T>::value should be false if T is not a MyClass type e.g T = vector<int>

Answer 1

template <class T>
struct IsClassName { static const bool value = false; };

template <class param1, param2, ...>
struct IsClassName<ClassName<param1, param2, ...> > { static const bool value = true; };