c++ - 如何在类定义中调用指针成员函数？

Question

如何在类定义中调用指针成员函数？我的代码:

//Myclass.h

struct Booking{
  int src;
  int dest;
  int pos;
};

class MyClass{
public:
    void ExecutePlan();
private:
    struct FlightPlan{
      string name;
      vector<Booking> bookings
    };

    typedef FlightPlan FP;
    FP firstplan;
    FP secondplan;
    void FirstPlan(Booking& book);
    void SecondPlan(Booking& book);
    void Execute(FP& fplan, void (MyClass::*mptr)(Booking& book));
};

// Myclass.cpp
void MyClass::FirstPlan(Booking& book){
// do something with booking
}

void MyClass::SecondPlan(Booking& book){
// do something with booking
}

void MyClass::Execute(FP& fplan, void(MyClass::*mptr)(const FlightPlan& fp)){
    for (int i=0; i<.fplan.bookings.size(); i++){
        cout << "Executing Plan: "<< fplan.name << endl;

       // Problematic line ...
        mptr(bookings[i]);   // <----- can't compile with this
    }
}

void MyClass::Execute(){
// is this the correct design to call this member functions ???

   Execute(firstplan, &MyClass::FirstPlan)   
   Execute(secondplan, &MyClass::SecondPlan)   
}

我如何构造执行函数以接收成员函数作为指针？

请问:我是C++的新手，也许设计很奇怪!!

保罗

Answer 1

How to call pointer member function inside a class definition?

与成员名称不同，成员指针不会隐式应用于this。你必须明确:

(this->*mptr)(fplan.bookings[i]);

is this the correct design to call this member functions ???

除了一些明显的错误(例如缺少 ; ，在 const FlightPlan& 的定义中你指的是 Booking& Execute)，其余代码看起来没问题。具体

Execute(firstplan, &MyClass::FirstPlan)   
Execute(secondplan, &MyClass::SecondPlan)   

是获取成员函数指针的正确语法。