javascript - 搜索 javascript 字符串并获取单词索引而不是字符

Question

我想在 javascript 字符串中搜索并按单词索引获取所有字符串出现次数，例如:

var str = 'Hello this is my this is world'
myFindWordIndex(str, 'this is') ==> [1, 4]

(搜索字符串出现两次，一次从 word 索引 1 开始，一次从索引 4 开始)解决方案可以使用JQuery

Answer 1

我会将您要查找的短语以及您要查找的位置拆分成单词。然后只需检查该短语是否包含搜索短语的每个部分。

function check(hay, needle, from) {
  var i = 1;
  while (i < needle.length) {
    if (hay[from] != needle[i])
      return false;
    i++;
    from++;
  }
  return true;
}

function myFindWordIndex(str, findme) {
  var indices = [];
  var needle = findme.split(" ");
  var hay = str.split(" ");

  for (var i = 0; i < hay.length - needle.length; i++) {
    if (hay[i] == needle[0] && (needle.length==1||check(hay, needle, i)))
      indices.push(i);
  }
  return indices;
}
var str = 'Hello this is my this is world';

console.log(myFindWordIndex(str, 'this is')); // ==> [1, 4]