javascript - 基于三个下拉菜单值的jquery选择器

Question

我正在处理三个下拉菜单，每个菜单都有三个选项。这三个下拉菜单一起创建了一个可以处于二十七种状态中的任何一种的系统。对于每个下拉列表，都有选项 1、选项 2 和全部(选项 1 和选项 2 的并集)。

根据这三个下拉菜单处于什么状态，我想显示或隐藏不同的div。这些 div 具有这种形式的类 class="distribution-(select-1)-(select-2)-(select-3)"

我正在尝试找到一种不依赖 27 种不同条件的 DRY 编码方式。

这是下拉菜单:

<div  style = "margin-top:1cm; font-size:125%">
    <strong>Clickout Type&nbsp;</strong>
    <select class = "clickouts" >
        <option value = "all" selected="selected">All</option>
        <option value = "clickouts" >Clickouts</option>
        <option value = "preferred" >Preferred Clickouts</option>
    </select>
    <strong>Graph Type&nbsp;</strong>
    <select class = "graph-type" >
        <option value = "all" selected="selected">All</option>
        <option value = "hist" >Histograms</option>
        <option value = "percent" >Percent</option>
    </select>
    <strong>Roll-up Type&nbsp;</strong>
    <select class = "roll-up" >
        <option value = "all" selected="selected">All</option>
        <option value = "aggregate" >Aggregate</option>
        <option value = "granular" >Granular</option>
    </select>
</div>

以下是 div 类的一些示例:distribution-hist-clickouts-aggregate，distribution-percent-clickouts-aggregate，class="distribution-hist-clickouts-granular"，distribution-percent-clickouts-granular

这是前七个状态的 jquery:

$('.clickouts, .graph-type, .roll-up').change(function(){
    var graph_type = $('.graph-type').val(); 
    var roll_up = $('.roll-up').val();
    var clickouts = $('.clickouts').val(); 

    if (graph_type == 'all' & roll_up == 'all' & clickouts == 'all'){
        $('div[class*="distribution"]').css('display', 'block');
    }
    if (graph_type == 'all' & roll_up == 'all' & clickouts == 'clickouts'){
        $('div[class*="clickout"]').css('display', 'block');
        $('div[class*="preferred"]').css('display', 'none');
    }

    else if (graph_type == 'all' & roll_up == 'all' & clickouts == 'preferred'){
        $('div[class*="clickout"]').css('display', 'none');
        $('div[class*="preferred"]').css('display', 'block');
    }

    else if (graph_type == 'hist' & roll_up == 'all' & clickouts == 'all'){
        $('div[class*="hist"]').css('display', 'block');
        $('div[class*="percent"]').css('display', 'none');
    }

    else if (graph_type == 'percent' & roll_up == 'all' & clickouts == 'all'){
        $('div[class*="hist"]').css('display', 'none');
        $('div[class*="percent"]').css('display', 'block');
    }

    else if (graph_type == 'all' & roll_up == 'aggregate' & clickouts == 'all'){
        $('div[class*="aggregate"]').css('display', 'block');
        $('div[class*="granular"]').css('display', 'none');
    }

    else if (graph_type == 'all' & roll_up == 'granular' & clickouts == 'all'){
        $('div[class*="aggregate"]').css('display', 'none');
        $('div[class*="granular"]').css('display', 'block');
    }
});

Answer 1

如果您要将复杂类 class="distribution-(select-1)-(select-2)-(select-3) 更改为一组类 class="distribution (select-1) (select-2) (select-3)您可以使用以下脚本:

$('.clickouts, .graph-type, .roll-up').change(function(){
    var graph_type = $('.graph-type').val(); 
    var roll_up = $('.roll-up').val();
    var clickouts = $('.clickouts').val(); 

    graph_type = (graph_type == "all" ? "" : "." + graph_type);
    roll_up = (roll_up == "all" ? "" : "." + roll_up);
    clickouts = (clickouts == "all" ? "" : "." + clickouts);

    var selector = '#container div' + graph_type + roll_up + clickouts;

    $('#container div:visible').hide();
    $(selector).show();
});

代码:http://jsfiddle.net/9R5zj/9/