javascript - 如何删除 casperjs 事件监听器

Question

我有一个如下定义的监听器:

function loadFailed() {
   casper.echo("load failed catched");
}

casper.on('load.failed', loadFailed);

... some code

casper.removeListener('load.failed', loadFailed);

//redefine loadFailed function
function loadFailed(e) {
    flagLoadFailed = true;
}

b.casper.on('load.failed', loadFailed);

然后我让两个函数在//中工作，而不是用新的实例删除第一个实例。

是否有任何方法可以删除代码中某处的监听器(并可能恢复原始监听器)？

Answer 1

您是否尝试过类似的操作:-

casper.on('load.failed', loadFailed)
...
casper.removeListener('load.failed', loadFailed);

function loadFailed(e) {
  ...
}

对于测试脚本，您可以使用安装和拆卸，例如

casper.test.begin('Missing resources', 1, {

    setUp: function () {
        // Attach the resource listener
        casper.on('resource.received', this.onResourceReceived);
    },

    tearDown: function () {
        // Remove the resource listener
        casper.removeListener('resource.received', this.onResourceReceived);
    },

    test: function (test) {
        casper.start(...);

        casper.run(function () {
            test.done();
        });
    },

    onResourceReceived: function (resource) {
        if (resource.stage === 'end' && resource.status === 404) {
            require('utils').dump(resource);
        }
    }
});