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javascript - 保持选择持久

转载 作者:行者123 更新时间:2023-11-27 22:36:57 28 4
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我需要在页面重新加载时保持选定的值不变。我正在使用带有 jQ​​uery 的多选插件作为下拉选择菜单。这可能吗?我对此了解不多,所以如果我听起来很蠢,对不起。 :)

<select multiple="multiple" style="width: 135px;" name="platform[]" id="platform">
<option value="platform_1">Platform 1</option>
<option value="platform_2">Platform 2</option>
</select>

<select id="2" multiple="multiple" style="width: 165px;" name="features[]" id="features">
<optgroup label="Group One">
<option value="feature_1">Feature 1</option>
<option value="feature_2">Feature 2</option>
<option value="feature_3">Feature 3</option>
<option value="feature_4">Feature 4</option>
<option value="feature_5">Feature 5</option>
<optgroup label="Group Two">
<option value="feature_6">Feature 6</option>
<option value="feature_7">Feature 7</option>
<option value="feature_8">Feature 8</option>
</select>

最佳答案

这是您可能需要的示例:

$("#platform").val(getCookie("platform"));
$("#2").val(getCookie("feature"));

$("#platform option").click(function(){
document.cookie = "platform="+$(this).val();
});
$("#2 option").click(function(){
document.cookie = "feature="+$(this).val();
});

function getCookie(c_name) {
var i,x,y,ARRcookies=document.cookie.split(";");
for (i=0;i<ARRcookies.length;i++) {
x=ARRcookies[i].substr(0,ARRcookies[i].indexOf("="));
y=ARRcookies[i].substr(ARRcookies[i].indexOf("=")+1);
x=x.replace(/^\s+|\s+$/g,"");
if (x==c_name)
{
return unescape(y);
}
}
}

jsfiddle

关于javascript - 保持选择持久,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13419241/

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