javascript - 在 if 语句中使用 Javascript 对象变量

Question

我正在使用 javascript 来显示购物篮的信息。我知道如何提取数据并从中创建元素，但我需要使用 if 语句的变量之一，并且不确定如何操作。

如果这是 true: "isPunchOut": false, 那么我想用 jQuery 来定位它，并执行类似 $(".button"的操作).remove();

我该怎么做？

var retailerData = {
"del": {
    "zip": "",
    "city": ""
},
"user": {
    "country": "",
    "phone": "",
    "nbrOrders": 0,
    "isPunchOut": false,
    "name": "",
    "salesPerson": "",
    "customerNo": "",
    "email": ""
},
"order": {
    "shippingSum": 0.0,
    "shippingFormatSum": "\u20AC0",
    "orderno": "0",
    "orderFormatSum": "\u20AC130",
    "voucher": "",
    "orderFormatVat": "\u20AC27,30",
    "currencySymbol": "\u20AC",
    "currency": "EUR",
    "orderVat": 27.3,
    "orderSum": 130.0,
    "items": [{
        "imageURI": "\/imgr\/8c82380c-65f5-43aa-83ad-fae1215b5b39\/70\/70",
        "qtyAvail": 7,
        "price": 130.0,
        "qty": 1,
        "artno": "D630-T7100-GE-REF",
        "vat": 27.3,
        "formatVat": "\u20AC27,30",
        "id": "52307",
        "label": "D630 C2D-T7100/2GB/80GB/DVD/14"/NO COA WLAN",
        "category": "Computers - Notebooks",
        "formatPrice": "\u20AC130",
        "manufacturer": "Dell"
    }]
  }
 }

Answer 1

您可以看一下下面的JS代码作为引用:

var isPunchOut = retailerData["user"]["isPunchOut"];
if(isPunchOut === false)
    $(".button").remove();