c++ - 为什么我不能将字符串传递给函数 GetDriveTypesA()？

Question

所以该程序的目的是找出可用的驱动器以及它们是什么。但是，我似乎无法将字符串变量直接传递给 GetDriveTypesA()。但是，如果我只是执行 GetDriveTypesA("C:\\") 它就会成功。

请有人帮我找到解决这个问题的方法，程序如下。谢谢:)

#include <iostream>
#include <windows.h>
#include <string>

using namespace std;

int main() {
    int i;
    int driveType;
    std::string path;
    int binary[26] = {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0}; //To save the binary number of the GetLogicalDrives
    std::string  actualDrives[26];
    std::string letters[26] = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"}; //letters of the alphabet
    DWORD drives = GetLogicalDrives(); //finds the bit mask of logical drives

    for(i=0; drives>0; i++) { //changes the integer into a binary number
        binary[i]=drives%2;
        drives= drives/2;
    }
    for (i=0; i<26; i++){ //finds out what drive letters are available
        if (binary[i]==1){
            actualDrives[i] = letters[i];
        }
    }
    for (i=0; i<26; i++){ \trying to find the drive type
        if (actualDrives[i] != ""){
        cout << "Actual drive:";
        cout<< actualDrives[i] <<endl;
        path = actualDrives[i] + ":\\";
        cout << path <<endl;
        driveType = GetDriveTypeA(path); //the part of the code that does not work but does work if a string is just entered
        cout<< driveType << endl;
        }
    }

}

Answer 1

因为 GetDriveTypeA()需要 C string ，不是 C++ std::string。

UINT GetDriveTypeA(
  LPCSTR lpRootPathName
);

使用 std::string.c_str()方法:

driveType = GetDriveTypeA(path.c_str());