c++ - 我怎样才能让这个简单的程序在不关闭的情况下返回？

Question

我今晚开始尝试学习 C++，现在我只是在 IDE 中闲逛。我怎样才能让这个简单的程序在您猜对数字(5、6 或 7)之前不关闭程序？

就目前而言，它将接受一个输入，然后说按任意键关闭，而不是让我继续猜测。

#include <iostream>

int main() 
{
    int favorite_number;

    std::cout << "Enter your favorite number between 1 and 100: ";
    std::cin >> favorite_number;

        if(favorite_number == 5 || favorite_number == 6 || favorite_number == 7)
        {
        std::cout << "Amazing!! That's my favorite number too!";
        }

    std::cout << "Nice try, but that's not my favorite number" << std::endl;
    return 0;
}

Answer 1

谢谢，明白了!

#include <iostream>

int main() 
{
    int favorite_number;
    bool completed = false;

    while(completed == false)
    {
    std::cout << "Enter your favorite number between 1 and 100: ";
    std::cin >> favorite_number;

        if(favorite_number == 5 || favorite_number == 6 || favorite_number == 7)
        {
        std::cout << "Amazing!! That's my favorite number too!";
        completed = true;
        return 0;
        }
        else
             std::cout << "Nice try, but that's not my favorite number" << std::endl;

        }


    return 0;
}