gpt4 book ai didi

c++ - 必须进行哪些更改才能使此 Windows 文本框从 2011 年开始在 2019 年正常运行?

转载 作者:行者123 更新时间:2023-11-27 22:34:40 25 4
gpt4 key购买 nike

要使此 Windows 文本框从 2011 年开始在 2019 年正常工作,必须进行哪些更改?

我尝试编译 this question from 2011 中的代码关于制作 C++ 文本框...

#include <windows.h>

#pragma comment(linker,"/manifestdependency:\"type='win32' name='Microsoft.Windows.Common-Controls' version='6.0.0.0' processorArchitecture='x86' publicKeyToken='6595b64144ccf1df' language='*'\"")

LRESULT CALLBACK WndProc(HWND hWnd, UINT msg, WPARAM wParam, LPARAM lParam);

int APIENTRY WinMain(HINSTANCE hInstance, HINSTANCE hPrevInstance, LPSTR nCmdLine, int nCmdShow)
{
LPTSTR windowClass = TEXT("WinApp");
LPTSTR windowTitle = TEXT("Windows Application");
WNDCLASSEX wcex;

wcex.cbClsExtra = 0;
wcex.cbSize = sizeof(WNDCLASSEX);
wcex.cbWndExtra = 0;
wcex.hbrBackground = (HBRUSH)(COLOR_WINDOW + 1);
wcex.hCursor = LoadCursor(NULL, IDC_ARROW);
wcex.hIcon = LoadIcon(NULL, IDI_APPLICATION);
wcex.hIconSm = LoadIcon(NULL, IDI_APPLICATION);
wcex.hInstance = hInstance;
wcex.lpfnWndProc = WndProc;
wcex.lpszClassName = windowClass;
wcex.lpszMenuName = NULL;
wcex.style = CS_HREDRAW | CS_VREDRAW;
if (!RegisterClassEx(&wcex))
{
MessageBox(NULL, TEXT("RegisterClassEx Failed!"), TEXT("Error"), MB_ICONERROR);
return EXIT_FAILURE;
}

HWND hWnd;

if (!(hWnd = CreateWindow(windowClass, windowTitle, WS_OVERLAPPEDWINDOW, CW_USEDEFAULT, CW_USEDEFAULT, CW_USEDEFAULT, CW_USEDEFAULT, NULL, NULL, hInstance, NULL)))
{
MessageBox(NULL, TEXT("CreateWindow Failed!"), TEXT("Error"), MB_ICONERROR);
return EXIT_FAILURE;
}

HWND hWndEdit = CreateWindow(TEXT("Edit"), TEXT("test"), WS_CHILD | WS_VISIBLE | WS_BORDER, 100, 20, 140, 20, hWnd, NULL, NULL, NULL);

ShowWindow(hWnd, nCmdShow);
UpdateWindow(hWnd);

MSG msg;

while (GetMessage(&msg, NULL, 0, 0))
{
TranslateMessage(&msg);
DispatchMessage(&msg);
}
return EXIT_SUCCESS;
}

LRESULT CALLBACK WndProc(HWND hWnd, UINT msg, WPARAM wParam, LPARAM lParam)
{
switch (msg)
{
case WM_DESTROY:
PostQuitMessage(EXIT_SUCCESS);
default:
return DefWindowProc(hWnd, msg, wParam, lParam);
}
return FALSE;
}

但尝试在 Visual Studio 2019 中构建它时,我收到有关无法将“t_char”转换为“LPTSTR”的错误。

那么,我该如何更新代码才能工作呢?不包含任何其他文件是否可能?

最佳答案

使用 LPCTSTR 代替 LPTSTR:

LPCTSTR windowClass = TEXT("WinApp");
LPCTSTR windowTitle = TEXT("Windows Application");

LPTSTRTCHAR *

LPCTSTRconst TCHAR *

TEXT("literal") 生成一个 const TCHAR []

字符串文字是常量数据。从 C++11 开始,您不能再将字符串文字分配给指向非常量的指针。

关于c++ - 必须进行哪些更改才能使此 Windows 文本框从 2011 年开始在 2019 年正常运行?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56307075/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com