javascript - 理解 typescript 继承

Question

我的问题的灵感来自this question

这是 typescript 继承代码

var __extends = (this && this.__extends) || function (d, b) {
    for (var p in b) if (b.hasOwnProperty(p)) d[p] = b[p];
    function __() { this.constructor = d; }
    __.prototype = b.prototype;
    d.prototype = new __();
};

我将版本简化为这个版本

function extend(Destination, Base) {
    function Hook() { this.constructor = Destination; }
    Hook.prototype = Base.prototype;
    var hook = new Hook();
    Destination.prototype = hook;
};

我绘制图形表示的灵感来自 here :

您能确认或更正文字表示吗？
我特别不明白这部分:

function Hook() { this.constructor = Destination; }

你能告诉我继承如何使用参数和附带的示例

Answer 1

这有什么帮助吗，我根据当前的 __extends 注释了每一行以说明它的作用。函数(与您的示例略有不同)

var extend = function (subType, superType) {

    // Copy superType's own (static) properties to subType
    for (var property in superType) {
        if (superType.hasOwnProperty(property)) {
            subType[p] = superType[p];
        }
    }

    // Create a constructor function and point its constructor at the subType so that when a new ctor() is created, it actually creates a new subType.
    function ctor() {
        this.constructor = subType;
    }

    if(superType === null) {

        // Set the subType's prototype to a blank object.
        subType.prototype = Object.create(superType);

    } else {

        // set the ctor's prototype to the superType's prototype (prototype chaining)
        ctor.prototype = superType.prototype;

        // set the subType's prototype to a new instance of ctor (which has a prototype of the superType, and whos constructor will return a new instance of the subType)
        subType.prototype = new ctor();
    }
};

请注意__extends可能会在不久的将来再次发生变化，包括使用 Object.setPrototypeOf(...);

GitHub - Change Class Inheritance Code