C++ 完全跳过一个开关

Question

我必须为我的计算机科学课编写一个简单的程序，我的老师要我使用循环和开关打印出十二天的圣诞歌曲，我正在尝试运行这段代码，但开关被跳过了完全地。如果你能帮助我，那就太好了，谢谢!

#include <iostream>
using namespace std;
int main()
{
 for (int i = 12; i > 0; i--) 
 {
    cout << "On the " << i << " day of Christmas my true love gave to me, \n";
    switch (i)
    {
        case 1: "Twelve drummers drumming\n";
        case 2: "Eleven pipers piping\n";
        case 3: "Ten lords a-leaping\n";
        case 4: "Nine ladies dancingn";
        case 5: "Eight maids a-milking\n";
        case 6: "Seven swans a-swimming\n";
        case 7: "Six geese a-laying\n";
        case 8: "Five gold rings\n";
        case 9: "Four colly birds\n";
        case 10: "Three french hens\n";
        case 11: "Two turtle doves, and\n";
        case 12: "A partridge in a pear tree\n";
                break;
    }
 }
system("pause");
return 0;
}

Answer 1

除了评估字符串文字(并丢弃该值)之外，您的 switch 没有做任何事情。替换你的每个案例:

case X: std::cout << "the string...\n";