javascript - 网站 - 根据鼠标位置更改图像(2 个区域)

Question

我的情况很简单(1 页，3 个区域:左 - 中 - 右):

HTML:

<div class="page">
    <div class="answer-on-the-right-or-left">
        Left zone
    </div>

    <div class="picture-in-the-middle">
        <img src="@Url.Content("/content/images/qres/faceblackandwhite.png")"/>
    </div>

    <div class="answer-on-the-right-or-left">
        Right zone
    </div>
</div>

CSS:

.page { width: 800px; height: 500px; }

.answer-on-the-right-or-left { float: left; width : 300px; height: 500px; }

.picture-in-the-middle { float: left; width : 150px; height: 500px; }

我想做以下事情:

• 当鼠标在左侧区域时，中间的图片变为:"/content/images/qres/facecolorleft.png"
• 当鼠标在右侧区域时:"/content/images/qres/facecolorright.png"
• 在其他任何地方，图像都会保留:"/content/images/qres/faceblackandwhite.png"

我知道如何使用 javascript 在图片上进行鼠标悬停，但我找不到解决此问题的方法。

提前致谢!

Answer 1

为每个区域分配一个 id:

<div class="answer-on-the-right-or-left" id="leftZone">Left Zone</div>
<div class="answer-on-the-right-or-left" id="rightZone">Right Zone</div>

并绑定(bind)悬停

$('.answer-on-the-right-or-left').hover(function() {
   var id = $(this).attr('id');
   var img = $('.picture-in-the-middle img');

   if(id == 'leftZone') img.attr('src', '/content/images/qres/facecolorleft.png');
   else if(id == 'rightZone') img.attr('src', '/content/images/qres/facecolorright.png');

}, function() {
   $('.picture-in-the-middle img').attr('src', '/content/images/qres/faceblackandwhite.png');
});