python - 如何将这些正则表达式合并为一个？

Question

(开始之前:我在 python 中执行此操作)

所以基本上我需要我的单个正则表达式来匹配我的 html QUOT 标签前后的所有引号:如果这些空格中存在引号，我需要它匹配。

例子:

<QUOT.START> Hello, this doesn't match! <\QUOT.END> 

"<QUOT.START> "Hello, this will call 4 matches! " <\QUOT.END> "

为此我有 4 个不同的正则表达式:

1.   \"+(?=<QUOT\.START>)

2.   (?<=<QUOT\.START>)\"+

3.   \"+(?=<\\QUOT\.END>)

4.   (?<=<\\QUOT\.END>)\"+

我可以将这 4 个基本合并为一个吗？

Answer 1

如果您能够使用较新的 regex module (它支持无限后视)你可以将你的表达稍微浓缩成

(?<=<\\?QUOT\.(?:START|END)>[\t ]*)" # matches quotes after <quot.start> or <quot.end>
                                     # plus whitespaces, eventually
|
"(?=[\t ]*<\\?QUOT\.(?:START|END)>)  # before <quot.start> or <quot.end>,
                                     # plus whitespaces eventually

---

没有详细模式:

(?<=<\\?QUOT\.(?:START|END)>[\t ]*)"|"(?=[\t ]*<\\?QUOT\.(?:START|END)>)

---

一般来说是这样的:

(?<=<tag><whitespaces, eventually>)quote|quote(?=<whitespaces, eventually><tag>)

---

在 Python 中:

import regex as re

string = """
<QUOT.START> Hello, this doesn't match! <\QUOT.END> 
"<QUOT.START> "Hello, this will call 4 matches! " <\QUOT.END> "
"""

rx = re.compile(r'''(?<=<\\?QUOT\.(?:START|END)>[\t ]*)"|"(?=[\t ]*<\\?QUOT\.(?:START|END)>)''')

for m in rx.finditer(string):
    print(m.group(0))
    print(m.span())

这会显示四个引号及其位置。