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c++ - 虽然循环比我指定的要循环更多次

转载 作者:太空宇宙 更新时间:2023-11-04 15:47:51 32 4
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我正在制作一个时钟驱动的模拟程序,除此之外,还有我的主要 while 循环,while(jobsCompleted < jobsToComplete)比预期/想要的循环次数更多。例如,如果我要将 500 分配给 jobsToComplete ,程序结束时的输出会告诉我完成了 505 个作业。我已经尝试调试这个问题至少一个小时了,但无济于事。任何帮助表示赞赏。谢谢!

#include <iostream>
#include <string>
#include <stdlib.h>
#include <queue>
#include <fstream>
#include "job.cpp"

using namespace std;

int main()
{
ofstream cpuSim;
cpuSim.open("cpuSim.out.txt");

int clock = 0, jobsCompleted = 0, jobsToComplete = 0, probUser = 0, probability, id = 0;
jobType_t job_type;
int inWQ, outWQ, inCPUQ, outCPUQ, required, given, jobTypeInt, timeSpentInCPUqueue = 0, timeSpentInWaitQueue = 0, CPUidle = 0;
queue<job> CPUqueue, waitQueue;

int numIO = 0, numCPU = 0;

srand(time(NULL));

cout << "Enter how many jobs need to be completed: ";
cin >> jobsToComplete;
cout << endl << "Enter the probability that a new job is created: ";
cin >> probUser;
cout << endl;

while(jobsCompleted < jobsToComplete)
{
clock++;
probability = rand() % 100 + 1;

if(probability > probUser)
{
for(int i=0; i<jobsToComplete; i++)
{
id = rand() % 1000 + 1;
jobTypeInt = rand() % 100 + 1;
if(jobTypeInt >= 50)
job_type = IO_bound;
else
job_type = CPU_bound;
required = rand() % 10;
job *newJob = new job(id, job_type, inWQ, outWQ, inCPUQ, outCPUQ, required, given);
waitQueue.push(*newJob);
}

while((CPUqueue.size() <= 10) && waitQueue.empty() == false)
{
waitQueue.front();
job temp = waitQueue.back();
waitQueue.pop();
temp.setTimeExitedWQueue(clock);
temp.setTimeEnteredCPUQueue(clock);
CPUqueue.push(temp);
}

double oneSecond = 1.0, timeSpent = 0;

while((oneSecond > 0.0) && (!CPUqueue.empty()))
{
job top = CPUqueue.front();
CPUqueue.pop();
if(top.getJobType() == IO_bound)
{
top.setTimeGiven(top.getTimeGiven() + .1);
timeSpent = .1;
numIO++;
}
else
{
top.setTimeGiven(top.getTimeGiven() + .2);
timeSpent = .2;
numCPU++;
}

if(top.getTimeRequired() <= top.getTimeGiven())
{
top.setTimeExitedCPUQueue(clock);
jobsCompleted++;

timeSpentInWaitQueue += (top.getTimeExitedWQueue() - top.getTimeEnteredWQueue());
timeSpentInCPUqueue += (top.getTimeExitedCPUQueue() - top.getTimeEnteredCPUQueue());
}
else
CPUqueue.push(top);
oneSecond -= timeSpent;

if((clock%60 == 0) && (clock > 600)) //every 60 seconds after the first 10 minutes
{
cout << "After the first 10 minutes:" << endl;
cout << "Time: " << clock << endl;
cout << "Number of jobs in the wait queue: " << waitQueue.size() << endl;

cout << "Number of jobs in the CPU queue: " << CPUqueue.size() << endl;
job temp1 = waitQueue.front();
job temp2 = CPUqueue.front();
cout << "Job number of front wait job: " << temp1.getID() << endl;
cout << "Job number of front CPU job: " << temp2.getID() << endl;
}
else
{
cout << "Job Number: " << jobsCompleted << endl;
cout << "Job ID: " << top.getID() << endl;
cout << "Job Type: " << top.getJobType() << endl;
cout << "Time in CPU Queue: " << timeSpentInCPUqueue << endl;
cout << "Time Entered CPU Queue: " << top.getTimeEnteredCPUQueue() << endl << endl;
}
}

if((oneSecond > 0) && (CPUqueue.empty()))
CPUidle += oneSecond;
}
}
cout << "I/O_bound jobs: " << numIO << endl;
cout << "CPU_bound jobs: " << numCPU << endl;
cout << "*****JOBS COMPLETED: " << jobsCompleted << " *****" << endl << endl;

return 0;
}

作为一个不太相关的问题,我无法正确打印我的枚举数据类型,也无法在最开始将我的 ID 传递到 *newJob 中。正确...

最佳答案

假设它已经循环了一段时间,现在 jobsCompleted 是 499(而您的 jobsToComplete 是 500)。好的,所以这是最后一个循环,对吗?是的!但是 jobsCompleted 的递增发生在另一个嵌套的 while 循环中。因此,如果该嵌套循环发生 6 次,jobsCompleted 将为 505,然后外部 while 循环将结束,使您完成的作业总数为 505。

告诉您如何修复它需要理解您的代码的逻辑,但有太多的东西让我无法弄清楚。也许这会对您有所帮助。

关于c++ - 虽然循环比我指定的要循环更多次,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13754443/

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