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c++ - find_if 的 Lambda 表达式

转载 作者:太空宇宙 更新时间:2023-11-04 15:41:41 25 4
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我目前正试图在 vector V 中找到一个元素。但我得到了很多错误。

bool VNS::remove(const HostName& name){ ^在/usr/lib/gcc/x86_64-pc-cygwin/4.8.2/include/c++/algorithm:62:0 包含的文件中, 来自 vns.cc:2:.....

 bool VNS::remove(const HostName& name){
auto it=find_if(v.begin(),v.end(),[](const HostName& a, const HostName& b){return a==b;});
//code that will remove the elem.
if(it!=v.end()){
return true;
}else{
return false;
}
}
HeaderFile:
class VNS:public NameServerInterface{
public:
/*
* Insert a name/address pair. Does not check if the name
* or address already exists.
*/
virtual void insert(const HostName&, const IPAddress&);

/*
* Remove the pair with the specified host name. Returns true
* if the host name existed and the pair was removed, false
* otherwise.
*/
virtual bool remove(const HostName&);

/*
* Find the IP address for the specified host name. Returns
* NON_EXISTING_ADDRESS if the host name wasn't in the name
* server.
*/
virtual IPAddress lookup(const HostName&) const;

private:
std::vector<std::pair<HostName,IPAddress> > v;
};

接口(interface):

/*
* Interface NameServerInterface -- all name server implementations must
* implement this interface.
*/
#ifndef NAME_SERVER_INTERFACE_H
#define NAME_SERVER_INTERFACE_H

#include <string>

using HostName = std::string;
using IPAddress = unsigned int;
const IPAddress NON_EXISTING_ADDRESS = 0;

class NameServerInterface {
public:
virtual ~NameServerInterface() = default;

/*
* Insert a name/address pair. Does not check if the name
* or address already exists.
*/
virtual void insert(const HostName&, const IPAddress&) = 0;

/*
* Remove the pair with the specified host name. Returns true
* if the host name existed and the pair was removed, false
* otherwise.
*/
virtual bool remove(const HostName&) = 0;

/*
* Find the IP address for the specified host name. Returns
* NON_EXISTING_ADDRESS if the host name wasn't in the name
* server.
*/
virtual IPAddress lookup(const HostName&) const = 0;
};

#endif

我的 lambda exp 有两个参数。编译器如何知道应该如何用正确的值替换它们。

最佳答案

您的错误消息转录遗漏了最有趣的部分:错误消息!

然而,问题似乎很明显:find_if 函数只需要一个参数,因此您需要捕获name,这就是[] 用于:

auto it=find_if(v.begin(),v.end(),
[&name](const HostName& a){return a==name;});

reference page很好地解释了 lambda。

关于c++ - find_if 的 Lambda 表达式,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21972179/

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