PHP - 上传多张图片

Question

我需要通过表单上传多张图片。我以为我会毫无问题地做到这一点，但我有一个。

当我尝试执行 foreach 并逐张获取图像时，它并没有像我希望的那样表现。

HTML

<form method="post" action="" enctype="multipart/form-data" id="frmImgUpload">
    <input name="fileImage[]" type="file" multiple="true" />
    <br />
    <input name="btnSubmit" type="submit" value="Upload" />
</form>

PHP

<?php
if ($_POST)
{
    echo "<pre>";
    foreach ($_FILES['fileImage'] as $file)
    {
        print_r($file);
        die(); // I want it to print first image content and then die to test this out...
        //imgUpload($file) - I already have working function that uploads one image
    }
}

我期望它打印出第一张图片，但它打印了所有图片的名称。

例子

Array
(
    [0] => 002.jpg
    [1] => 003.jpg
    [2] => 004.jpg
    [3] => 005.jpg
)

我想要它输出什么

Array
(
    [name] => 002.jpg
    [type] => image/jpeg
    [tmp_name] => php68A5.tmp
    [error] => 0
    [size] => 359227
)

那么我如何才能在循环中逐张选择图像以便我可以将它们全部上传？

好吧，我找到了解决方案，我就是这样做的，可能不是最好的方法，但它确实有效。

foreach ($_FILES['fileImage']['name'] as $f)
{
    $file['name'] = $_FILES['fileImage']['name'][$i];
    $file['type'] = $_FILES['fileImage']['type'][$i];
    $file['tmp_name'] = $_FILES['fileImage']['tmp_name'][$i];
    $file['error'] = $_FILES['fileImage']['error'][$i];
    $file['size'] = $_FILES['fileImage']['size'][$i];
    imgUpload($file);
    $i++;
}

Answer 1

该数组以另一种方式形成

是这样的:

array ( 
    'name' => array (
       [0] => 'yourimagename',
       [1] => 'yourimagename2',
       ....
    ),
    'tmp_file' => array (
    ....

应该这样做:

foreach ($_FILES['fileImage']['name'] as $file)
    {
        print_r($file);
        die(); // I want it to print first image content and then die to test this out...
        //imgUpload($file) - I already have working function that uploads one image
    }