C++ 字符串数组搜索每个项目的输出

Question

我知道这个问题的标题有点令人困惑，但我真的需要帮助。我需要在包含许多字符串的数组中找到一个字符串。如果未找到该字符串，则会显示相应的消息。然而，当我使用 for 循环时，它会为数组中的每个未找到的字符串显示此消息，尽管它也显示找到的字符串......我希望你明白我的意思，如果我没有意义，我很抱歉。这是我的代码:

void Store::search() {
        string name;
        cout << "Enter name of product you're searching: " << endl;
        getline(cin, name);

        for (int i = 0; i < quantity; i++) {
            if (name.compare(database[i].name) == 0){                           
            cout << "-------------<Product found!>-------------" << endl;
            cout << "name: " << database[i].name << endl;
            cout << "supplier: " << database[i].supplier << endl;
            cout << "available quantity: " << database[i].quantity<< endl;
            cout << "price per unit: " << database[i].price<< endl;
            cout << "------------------------------------------" << endl;
                }
            else
            {
                cout << "Product doesn't exist in database!" << endl;
            }
          }     

        }   

该代码适用于搜索，但如何停止输出“数据库中不存在产品!”对于数组中未找到的每个项目(即使找到搜索项目)？

提前谢谢你

Answer 1

您可以使用语句标志:

void Store::search() 
{
    string name;
    bool found = false
    cout << "Enter name of product you're searching: " << endl;
    getline(cin, name);

    for (int i = 0; i < quantity; i++) 
    {
        if (name.compare(database[i].name) == 0){                           
        cout << "-------------<Product found!>-------------" << endl;
        cout << "name: " << database[i].name << endl;
        cout << "supplier: " << database[i].supplier << endl;
        cout << "available quantity: " << database[i].quantity<< endl;
        cout << "price per unit: " << database[i].price<< endl;
        cout << "------------------------------------------" << endl;
        found = true;
        break;
    }

    if (!found)
       cout << "Product doesn't exist in database!" << endl;

}