c++ - 猜猜我的号码 c++ while loop inside a loop

Question

在学习 C++ 时，我可以简单地猜测我的数字代码。如您所见，它选择一个随机数并让用户猜测并记录尝试次数。

int main(){
   srand(static_cast<unsigned int>(time(0))); // seed number generator

   int secretNumber = rand() % 100 + 1;
   int tries = 0;
   int guess;

   cout << "\tWelcome to Guess my Number\n\n";
   do{
    cout << "Enter a guess: ";
    cin >> guess;
    ++tries;

    if (guess > secretNumber){
        cout << "Too high\n";
    } else if (guess < secretNumber){
        cout << "Too low \n";
    } else {
        cout << "You got it :) in " << tries << " tries \n\n";
    }
   } while(guess != secretNumber);
}

虽然这工作正常，但我也希望用户只能尝试 5 次。我可以考虑添加另一个 else if声明以确保(tries < 6) .

或

我可以在 do 中创建另一个 while 循环并确保 (tries < 6) .

这里最好的方法是什么？

Answer 1

您可以在do-while-loop中添加条件

int main(){
   srand(static_cast<unsigned int>(time(0))); // seed number generator

   int secretNumber = rand() % 100 + 1;
   int tries = 0;
   int guess;

   cout << "\tWelcome to Guess my Number\n\n";
   do{
    cout << "Enter a guess: ";
    cin >> guess;
    ++tries;

    if (guess > secretNumber){
        cout << "Too high\n";
    } else if (guess < secretNumber){
        cout << "Too low \n";
    } else {
        cout << "You got it :) in " << tries << " tries \n\n";
    }
   } while((guess != secretNumber) && (tries < 6));
}