javascript - 通过 XMLHttpRequest 预加载音频文件

Question

我目前正在尝试通过浏览器中的 XMLHttpRequest 预加载 MP3 文件并在音频播放器中播放。直接在播放器中设置时播放音频文件。因此，我在处理响应时一定有错误。

loadAudio : function(playerId, source) {
    var player = document.getElementById(playerId);
    var request = new XMLHttpRequest();
    request.onreadystatechange = function() {
        console.log('readyState: ' + request.readyState + ', status: ' + request.status)
        if (this.readyState == 4 && this.status == 200) {
            console.log(request.getAllResponseHeaders());
            var blob = new Blob( [request.response] );
            var url = URL.createObjectURL( blob );
            player.src = url;
            player.addEventListener('loaded', function(e) {
                URL.revokeObjectURL(player.src);
            });
            player.play();
        // Typical action to be performed when the document is ready:
        }
    };
    request.open("GET", source, true);
    request.send();
}

我收到以下错误消息:

DEMUXER_ERROR_COULD_NOT_OPEN: FFmpegDemuxer: open context failed (code 4)

有谁知道在哪里可以找到错误吗？谢谢您的回答。

Answer 1

您可以尝试将 ajax 请求中的响应类型设置为 blob。

loadAudio : function(playerId, source) {
    var player = document.getElementById(playerId);
    var request = new XMLHttpRequest();
    request.onreadystatechange = function() {
        console.log('readyState: ' + request.readyState + ', status: ' + request.status)
        if (this.readyState == 4 && this.status == 200) {
            var url = URL.createObjectURL( request.response);
            player.src = url;
            player.addEventListener('loaded', function(e) {
                URL.revokeObjectURL(player.src);
            });
            player.play();
        // Typical action to be performed when the document is ready:
        }
    };
    request.open("GET", source, true);
    request.responseType = 'blob';
    request.send();
}