java - 根据返回值计算平均值

Question

我想知道如何正确计算“平均步骤数等于”，因为步骤/N 在主方法中不起作用。如果我有 100/N，我的代码可以正确运行，但是我不确定如何总结 TestWalk 方法中的步骤，然后返回到 main。谢谢!

class Test { 

static int TestWalk() {

      int location = 5;
      int steps = 0;
      while (location != 0 && location !=10)
      {
         int direction = (int)(Math.random()*2);
         if (direction == 0)
         {
            location = location - 1;
         }
         if (direction == 1)
         {
            location = location + 1;
         }
         steps = steps + 1;
      }
      if (location == 0)
      {
         System.out.println ("Time for a walk!");
         System.out.println ("Took " + steps + " steps, and ");
         System.out.println ("Landed at HOME\n");
      }
      else
      {
         System.out.println ("Time for a walk!");
         System.out.println ("Took " + steps + " steps, and ");
         System.out.println ("Landed in Hospital\n");
      }
      return steps; }

      public static void main (String [] args) {
      final int N = 5;
      for(int i = 0; i<N; i++)
         TestWalk();
      System.out.println ("Average # of steps equals " + steps/N);
  }
}

Answer 1

您需要在main()中有一个steps变量，它将包含从TestWalk()返回的所有步骤的总和；方法。

int steps = 0; // this is local to main and has nothing do with the steps in TestWalk() method
for(int i = 0; i<N; i++) {
    steps += TestWalk(); // steps will keep the sum of all the steps
}
System.out.println ("Average # of steps equals " + steps/N);