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java - 处理 JSON 时出现异常

转载 作者:太空宇宙 更新时间:2023-11-04 15:23:03 26 4
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每当我运行此代码时,我总是会遇到此异常:

Error parsing data org.json.JSONException: Value {"requestStatus":"0"} 
of type org.json. JSONObject cannot be converted to JSONArray.

我已经检查过其他答案,但它们对我不起作用。

这是我的代码:

import java.util.ArrayList;
import org.apache.http.NameValuePair;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import com.example.footballtesting.CustomHttpClient;
import android.os.Bundle;
import android.os.StrictMode;
import android.app.Activity;
import android.util.Log;
import android.view.Menu;
import android.view.View;
import android.widget.EditText;
import android.widget.ImageButton;
import android.widget.RelativeLayout;
import android.widget.TextView;
public class MainActivity extends Activity {

TextView txt_view1;
TextView txt_view3;
TextView txt_view2;
EditText txt_teamID;
ImageButton btn_save;
ImageButton btn_show;
RelativeLayout Relativelayoutrequest;
boolean haveTeamRequest;;//to store the result of mysql query after decoding with JSON


@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
txt_view1=(TextView)findViewById(R.id.textView1);
txt_view2=(TextView)findViewById(R.id.textView2);
txt_view3=(TextView)findViewById(R.id.layout2textView1);
txt_teamID=(EditText)findViewById(R.id.txt_teamID);
btn_save=(ImageButton)findViewById(R.id.imgbtn_lsave);
btn_show=(ImageButton)findViewById(R.id.imgbtn_layout2);
Relativelayoutrequest=(RelativeLayout)findViewById(R.id.Relativelayoutrequest);
checkOnCreate();
}
public void checkOnCreate()
{
StrictMode.setThreadPolicy(new StrictMode.ThreadPolicy.Builder()
.detectDiskReads().detectDiskWrites().detectNetwork() // StrictMode is most commonly used to catch accidental disk or network access on the application's main thread
.penaltyLog().build());
Relativelayoutrequest=(RelativeLayout)findViewById(R.id.Relativelayoutrequest);
String response=null;
String st=null;
String str=null;
String memberID="000000011";
String returnString=null;
int status=1;
//To pass to php
ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>();
postParameters.add(new BasicNameValuePair("userID",memberID));

ArrayList<NameValuePair> pp = new ArrayList<NameValuePair>();
postParameters.add(new BasicNameValuePair("userID","409"));
try {

response = CustomHttpClient.executeHttpPost(
"http://10.0.2.2/football365/checkRequestFromTeam.php",
postParameters);//local host
}
catch (Exception e) {

e.printStackTrace();
}
String result = response.toString();
try{
returnString = "";
JSONArray jArray = new JSONArray(result);
for(int i=0;i<jArray.length();i++){
JSONObject json_data = jArray.getJSONObject(i);
Log.i("log_tag","requestStatus: "+json_data.getInt("requestStatus")
);
//Get an output to the screen
status=json_data.getInt("requestStatus");
}
}
catch(JSONException e){
Log.e("log_tag", "Error parsing data "+e.toString());
}



Log.i("str", status+"JJJJJJJJJJJJJJJJ");
Log.i("str", st+"BBBBBBBBBBBBBBBBBB");
Log.i("str", str+"CCCCCCCCCCCCCCCCCCCCCCCCCC");


}
}

最佳答案

JSONObject cannot be converted to JSONArray. 

您正在尝试将 JSONArray 用于 JSON 对象。
尝试一下

JSONObject obj = new JSONObject (result);

关于java - 处理 JSON 时出现异常,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20209729/

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