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c++ - 为什么在这种情况下调用复制构造函数?

转载 作者:太空宇宙 更新时间:2023-11-04 15:22:34 25 4
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我有这两个简单的类:CreditCard 和 Account

    #pragma once

#include<string>

class CreditCard
{
private:
std::string number;
int expMonth;
int expYear;
int pin;
public:

CreditCard():number(""), expMonth(0), expYear(0), pin(0)
{

}

CreditCard(std::string number, int expMonth, int expYear,int pin):number(number), expMonth(expMonth), expYear(expYear), pin(pin)
{
if(number.length()!=5)
{
throw std::invalid_argument("Card number must be 5 characters");
}
if(expMonth<0 || expMonth>12)
{
throw std::invalid_argument("Invalid expiration month");
}
if(expYear<2014 || expYear>2020)
{
throw std::invalid_argument("Invalid expiration year");
}
if(pin<1000 || pin>9999)
{
throw std::invalid_argument("PIN must be between 1000 and 9999");
}
}

CreditCard(const CreditCard &creditCard):number(creditCard.number), expMonth(creditCard.expMonth), expYear(creditCard.expYear), pin(creditCard.pin)
{

}

CreditCard(CreditCard &&creditCard):number(std::move(creditCard.number)), expMonth(std::move(creditCard.expMonth)), expYear(std::move(creditCard.expYear)), pin(std::move(creditCard.pin))
{
creditCard.number="";
creditCard.expMonth=0;
creditCard.expYear=0;
creditCard.pin=0;
}

CreditCard& operator = (const CreditCard &creditCard)
{
number=creditCard.number;
expMonth=creditCard.expMonth;
expYear=creditCard.expYear;
pin=creditCard.pin;
return *this;
}

CreditCard& operator = (CreditCard &&creditCard)
{
if(this!=&creditCard)
{
number=std::move(creditCard.number);
expMonth=std::move(creditCard.expMonth);
expYear=std::move(creditCard.expYear);
pin=std::move(creditCard.pin);
number=creditCard.number;
expMonth=creditCard.expMonth;
expYear=creditCard.expYear;
pin=creditCard.pin;
}
return *this;
}

std::string getNumber() const
{
return number;
}

int getExpMonth() const
{
return expMonth;
}

int getExpYear() const
{
return expYear;
}

int getPin() const
{
return pin;
}
};


#pragma once

#include<string>
#include"CreditCard.h"

class Account
{
private:
std::string number;
float amount;
CreditCard creditCard;
public:
Account():number(""), amount(0), creditCard()
{

}

Account(std::string number, float amount, CreditCard creditCard) : number(number), amount(amount), creditCard(creditCard)
{

}

Account(const Account &account) : number(account.number), amount(account.amount), creditCard(account.creditCard)
{

}

Account(Account &&account) : number(std::move(account.number)), amount(std::move(account.amount)), creditCard(std::move(creditCard))
{

}

Account& operator = (const Account &account)
{
number=account.number;
amount=account.amount;
creditCard=account.creditCard;
return *this;
}

Account& operator = (Account &&account)
{
if(this!=&account)
{
number=account.number;
amount=account.amount;
creditCard=account.creditCard;

account.number="";
account.amount=0;
account.creditCard=CreditCard("",0,0,0);
}
return *this;
}

std::string getNumber() const
{
return number;
}

float getAmount() const
{
return amount;
}

void deposit(const float &depositAmount)
{
amount+=depositAmount;
}

void withdraw(const float &withdrawAmount)
{
amount-=withdrawAmount;
}
};

在主要部分我有这一行:

Account account1("x12345x",1235.2, CreditCard("12345",1,2014,1122));

发生了什么:

  1. CreditCard 构造函数被调用
  2. CreditCard 移动构造函数被调用
  3. 调用账户构造函数
  4. CreditCard 复制构造函数被调用

我不明白为什么会出现 4。为什么要调用复制构造函数?

PS:感谢对这些类的任何更正。

最佳答案

I don't understand why 4 is happening. Why that copy constructor call?

那是因为这一行:

Account(std::string number, float amount, CreditCard creditCard) 
:
number(number), amount(amount), creditCard(creditCard)
// ^^^^^^^^^^^^^^^^^^^^^^
{ ... }

Account 的构造函数中,您将左值 creditCard 复制到成员变量 creditCard 中。这会调用 CreditCard 的复制构造函数。

实际上,由于您正在按值获取 creditCard,因此移动它是安全的:

Account(std::string number, float amount, CreditCard creditCard) 
:
number(number), amount(amount), creditCard(std::move(creditCard))
// ^^^^^^^^^^^^^^^^^^^^^
{ ... }

这将导致调用 CreditCardmove 构造函数,而不是第 4 步中的复制构造函数。

关于c++ - 为什么在这种情况下调用复制构造函数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15577016/

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