c++ - 使用带有多选标志的 GetOpenFileName() 时如何获取所选文件的列表？

Question

我试过谷歌搜索，但人们似乎遇到了同样的问题:我们无法获得所选文件的列表。

这是一段简单的工作代码，与我使用的代码类似:

OPENFILENAME ofn = { sizeof ofn };
wchar_t file[1024];
file[0] = '\0';
ofn.lpstrFile = file;
ofn.nMaxFile = 1024;
ofn.Flags = OFN_ALLOWMULTISELECT | OFN_EXPLORER;
GetOpenFileName(&ofn);

我实际上如何获得我选择的文件名？目前我只能在没有 OFN_ALLOWMULTISELECT 标志的情况下让它工作，所以它会将一个选定的文件名返回到 ofn.lpstrFile 中。我试图打印出该结构内的所有字符串变量，但一无所获。它只显示所选文件的主文件夹。

Answer 1

看起来 ofn.lpstrFile 包含所有文件名，以 NULL 分隔并以另一个 NULL 结尾(实际上以空字符串结尾)。

If the OFN_ALLOWMULTISELECT flag is set and the user selects multiple files, the buffer contains the current directory followed by the file names of the selected files. For Explorer-style dialog boxes, the directory and file name strings are NULL separated, with an extra NULL character after the last file name. For old-style dialog boxes, the strings are space separated and the function uses short file names for file names with spaces. You can use the FindFirstFile function to convert between long and short file names. If the user selects only one file, the lpstrFile string does not have a separator between the path and file name.

来自 MSDN .

解析内容的可能实现是；

wchar_t* str = ofn.lpstrFile;
std::wstring directory = str;
str += ( directory.length() + 1 );
while ( *str ) {
  std::wstring filename = str;
  str += ( filename.length() + 1 );
  // use the filename, e.g. add it to a vector
}