c++ - 将一小段代码从 c++11 转换为 c++03？

Question

我是一名试图编译 C++ 代码的社会科学家，遇到了一些小问题，我认为如果你了解 C++ 就很容易解决，但对我来说却难以理解。

尝试在 V2008 上编译，但我的代码似乎使用了一些 C++11 语法技巧。

In principle, I think this is solution ，但我真的不懂 C++，所以不确定如何实现。

代码块:

Optimiser::Optimiser(double eps, double delta, unsigned long max_itr, long random_order)
{
  this->eps = eps;
  this->delta = delta;
  this->max_itr = max_itr;
  this->random_order = random_order;
}

Optimiser::Optimiser() : Optimiser::Optimiser(1e-5, 1e-2, 1000, 1)
{
  //ctor
}

我得到的错误(引用 Optimiser::Optimiser() : Optimiser::Optimiser(1e-5, 1e-2, 1000,1) 行)是:

c:\Program Files (x86)\Common Files\Microsoft\Visual C++ for Python\9.0\VC\Include\xlocale(342) : warning C4530: C++ exception handler used, but unwind semantics are not enabled. Specify /EHsc
src\Optimiser.cpp(39) : error C2039: '{ctor}' : is not a member of 'Optimiser'        include\Optimiser.h(26) : see declaration of 'Optimiser'
src\Optimiser.cpp(40) : error C2614: 'Optimiser' : illegal member initialization: 'Optimiser' is not a base or member
error: command '"c:\Program Files (x86)\Common Files\Microsoft\Visual C++ for Python\9.0\VC\Bin\amd64\cl.exe"' failed with exit status 2

Answer 1

直到 C++11 才允许委托(delegate)构造函数。也就是说，您将复制代码，但您可以简单地将第二个构造函数更改为

Optimiser::Optimiser()
{
    eps = 1.0e-5;
    delta = 1.0e-2;
    max_itr = 1000UL;
    random_order = 1L;
    //rest of your ctor
}