c++ - 类方法包含相同的类对象

Question

在func1和func2中是否合法？类方法包含相同的类对象。

例子:

class Foo
{
public:
    void func1() {
        //...
        Foo foo; // Is it legal?
        //...
    }

    // Is it legal in paramete?
    void func2(Foo object) {
        //...
    }

    // It is legal using reference
    // http://stackoverflow.com/questions/6921185/why-do-objects-of-the-same-class-have-access-to-each-others-private-data
    void func3(Foo& object) {
        //
    }
};

Answer 1

Is it legal?

是的

Why?

class Foo
{
public:
    void func1() {
        //...
        Foo foo; // Is it legal?
        //...
    }
};

类成员函数的主体是在考虑了整个类定义之后编译的。

因此，整个类都可用于方法的实现，包括方法和在当前方法之后声明的成员。

这在[class.mem]中有介绍

Within the class member-specification, the class is regarded as complete within function bodies, default arguments, using-declarations introducing inheriting constructors, exception-specifications, and brace-or-equal-initializers for non-static data members (including such things in nested classes).