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java - 用户单击 AlertDialog OK 按钮后如何导航到下一个 Activity ?

转载 作者:太空宇宙 更新时间:2023-11-04 15:09:20 24 4
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很抱歉在http://stackoverflow.com搜索后提出这个问题。但在不同部分使用以下代码时,我无法处理下一个 Activity 。

这里,当用户未连接互联网时,将在alertdialog中弹出一个警告并显示“您未连接到互联网”,当用户单击alertdilog中的退出按钮时,应用程序将关闭。如果用户有互联网连接,则会弹出一个警告对话框,并在警报对话框中显示“您有互联网连接”,并且当用户单击继续按钮时,应用程序将继续执行下一个 Activity 。我在继续下一个 Activity 时遇到问题,该怎么办?

以下代码显示在其部分中

AndroidDetectInternetConnectionActivity.java中的代码

package com.example.detectinternetconnection;

import android.app.Activity;
import android.app.AlertDialog;
import android.content.Context;
import android.content.DialogInterface;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;

public class AndroidDetectInternetConnectionActivity extends Activity {

// flag for Internet connection status
Boolean isInternetPresent = false;

// Connection detector class
ConnectionDetector cd;

@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);

Button btnStatus = (Button) findViewById(R.id.btn_check);

// creating connection detector class instance
cd = new ConnectionDetector(getApplicationContext());

/**
* Check Internet status button click event
* */
btnStatus.setOnClickListener(new View.OnClickListener() {


@Override
public void onClick(View v) {

// get Internet status
isInternetPresent = cd.isConnectingToInternet();

// check for Internet status
if (isInternetPresent) {
// Internet Connection is Present
// make HTTP requests
AlertDialog.Builder builder = new AlertDialog.Builder(AndroidDetectInternetConnectionActivity.this);
builder.setMessage("You have network connection.")
.setTitle("Internet Connection")
.setCancelable(false);
AlertDialog alert = builder.create();
alert.setButton("Continue", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which){
// Do call some activity. Do what you wish to;
startActivity(new Intent(AndroidDetectInternetConnectionActivity.this,MainActivity2.class));
}
});
alert.show();
}

else {
// Internet connection is not present
// Ask user to connect to Internet
AlertDialog.Builder builder = new AlertDialog.Builder(AndroidDetectInternetConnectionActivity.this);
builder.setMessage("You need a network connection to use this application. Please turn on mobile network or Wi-Fi in Settings.")
.setTitle("No Internet Connection")
.setCancelable(false);
AlertDialog alert = builder.create();
alert.setButton2("Exit", new DialogInterface.OnClickListener(){
public void onClick(DialogInterface dialog, int which) {
//close the program
AndroidDetectInternetConnectionActivity.this.finish();
}
});
// Showing Alert Message
alert.show();
}
}

ConnectionDetector.java中的代码 包 com.example.Detectinternetconnection;

import android.app.AlertDialog;
import android.content.Context;
import android.net.ConnectivityManager;
import android.net.NetworkInfo;

public class ConnectionDetector {

private Context _context;

public ConnectionDetector(Context context){
this._context = context;
}

public boolean isConnectingToInternet(){
ConnectivityManager connectivity = (ConnectivityManager) _context.getSystemService(Context.CONNECTIVITY_SERVICE);
if (connectivity != null)
{
NetworkInfo[] info = connectivity.getAllNetworkInfo();
if (info != null)
for (int i = 0; i < info.length; i++)
if (info[i].getState() == NetworkInfo.State.CONNECTED)
{
return true;
}

}
return false;
}
}

AndroidManifest.xml中的代码

  <?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.example.detectinternetconnection"
android:versionCode="1"
android:versionName="1.0" >

<uses-sdk android:minSdkVersion="8" />

<application
android:icon="@drawable/ic_launcher"
android:label="@string/app_name" >
<activity
android:name=".AndroidDetectInternetConnectionActivity"
android:label="@string/app_name" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />

<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<activity android:name=".MainActivity2"></activity>
</application>

<!-- Internet Permissions -->
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

</manifest>

请告诉我哪里做错了?

最佳答案

总的代码很好,但最后只是通过create()创建初始化alertdialog..

    if (isInternetPresent) {              
// Internet Connection is Present
// make HTTP requests
AlertDialog.Builder builder = new AlertDialog.Builder(AndroidDetectInternetConnectionActivity.this);
builder.setMessage("You have network connection.")
.setTitle("Internet Connection")
.setCancelable(false);

alert.setPositiveButton("Continue", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which){
// Do call some activity. Do what you wish to;
startActivity(new Intent(AndroidDetectInternetConnectionActivity.this,MainActivity2.class));
}
});
AlertDialog alert = builder.create();
alert.show();

编辑

这是您的总 Activity 类别。

package com.example.detectinternetconnection;

import android.app.Activity;
import android.app.AlertDialog;
import android.content.DialogInterface;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;

public class AndroidDetectInternetConnectionActivity extends Activity implements OnClickListener {

Boolean isInternetPresent = false;
ConnectionDetector cd;

@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);

Button btnStatus = (Button) findViewById(R.id.btnStatus);
cd = new ConnectionDetector(getApplicationContext());
btnStatus.setOnClickListener(this);
}

@Override
public void onClick(View v) {
isInternetPresent = cd.isConnectingToInternet();
if (isInternetPresent) {

AlertDialog alert;
AlertDialog.Builder builder = new AlertDialog.Builder(
AndroidDetectInternetConnectionActivity .this);
builder.setTitle("Internet Connection");
builder.setCancelable(false);

builder.setPositiveButton("Continue",
new DialogInterface.OnClickListener() {

@Override
public void onClick(DialogInterface dialog, int which) {
// TODO Auto-generated method stub
startActivity(new Intent(AndroidDetectInternetConnectionActivity .this,
MainActivity2 .class));
}
});

alert = builder.create();
alert.show();
}

else {

AlertDialog alert;
AlertDialog.Builder builder = new AlertDialog.Builder(
AndroidDetectInternetConnectionActivity .this);
builder.setTitle("No Internet Connection");
builder.setMessage("Please Connect To Internet");
builder.setCancelable(false);

builder.setPositiveButton("Exit",
new DialogInterface.OnClickListener() {

@Override
public void onClick(DialogInterface dialog, int which) {

}
});

alert = builder.create();
alert.show();
}
}

}

我想你会照顾其他类(class)。有关一些知识,你可以引用Android Dialog开发者网站上的教程。

关于java - 用户单击 AlertDialog OK 按钮后如何导航到下一个 Activity ?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21546909/

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