java - 字符串版本比较

Question

这个问题已经有答案了:

How do you compare two version Strings in Java? (31 个回答)

已关闭 9 年前。

嗨，我有字符串数组

String version[] = {"3.1.2","2.1.7","3.1.1","3.7.3","2.6.4","1.3.4.7"};

我想在其中找到最新版本。哪种方法会好呢？它应该打印 3.7.3

Answer 1

这是一个使用比较器的示例

public static void main(String[] args) {
    String version[] = { "3.1.2", "2.1.7", "3.1222.1", "3.10.1", "3.10",
            "3.7.3", "2.6.4", "1.3.4.7" };
    Arrays.sort(version, new Comparator<String>() {

        @Override
        public int compare(String o1, String o2) {
            //Split tokens into arrays
            String[] tokens1 = o1.split("\\.");
            String[] tokens2 = o2.split("\\.");

            //Compare existing elements of each array
            for (int i = 0; i < tokens1.length && i < tokens2.length; i++) {
                int comparison = Integer.valueOf(tokens1[i]).compareTo(
                        Integer.valueOf(tokens2[i]));
                if (comparison != 0) {
                    return comparison;
                }
            }
            //Compare how specific each version is promote the most general
            //Only considered if version lengths != in size but equal in compared tokens
            return tokens1.length - tokens2.length;
        }

    });

    for (String v : version) {
        System.out.println(v);
    }
}