c++ - Project Euler 18 - C++ 通过引用传递数组

Question

参见:http://projecteuler.net/problem=18比我在这里给出的问题更好的解释。

我喜欢我的算法；这不是蛮力。我查看金字塔底部的所有 3x3 三角形来计算哪条路线最好，然后将该值分配回该行。这就是我的函数称为 ConsolidateBottomThreeRows 的原因——我最终会自下而上计算最佳路径，每次分配给底部 3 行中的最顶部，创建一个越来越小的金字塔，直到我的顶部行包含答案.

我的问题不是算法问题，只是语法问题。我无法弄清楚 [是的，即使使用谷歌搜索] 如何正确传递我的数组。这是我尝试编译时的输出:

C:\MyApps\Euler>g++ Prob_18.cpp -o Prob_18
Prob_18.cpp: In function 'void ConsolidateBottomThreeRows(int*, int*, int*)':
Prob_18.cpp:17:20: error: request for member 'size' in 'top', which is of non-class type 'int*'

还有我的代码:

#include <iostream>
using namespace std;

int CrunchSmallTriangle(int top[], int middle[], int bottom[])
{
    int biggest=0;
    if(middle[0]+bottom[0] > biggest) biggest=middle[0]+bottom[0];
    if(middle[0]+bottom[1] > biggest) biggest=middle[0]+bottom[1];
    if(middle[1]+bottom[0] > biggest) biggest=middle[1]+bottom[0];
    if(middle[1]+bottom[1] > biggest) biggest=middle[1]+bottom[1];
    return biggest+top[0];
}

void ConsolidateBottomThreeRows(int top[], int middle[], int bottom[])
{
    int SmallTop[0], SmallMiddle[2], SmallBottom[3];
    for(int x=0;x<top.size();x++)
    {
        SmallTop[0]=top[x];
        SmallMiddle[0]=middle[x];
        SmallMiddle[1]=middle[x+1];
        SmallBottom[0]=bottom[x];
        SmallBottom[1]=bottom[x+1];
        SmallBottom[2]=bottom[x+2];
        top[x]=CrunchSmallTriangle(SmallTop, SmallMiddle, SmallBottom);
    }
}

int main()
{
    int row1[1]={75};
    int row2[2]={95,64};
    int row3[3]={17,47,82};
    int row4[4]={18,35,87,10};
    int row5[5]={20,4,82,47,65};
    int row6[6]={19,1,23,75,3,34};
    int row7[7]={88,2,77,73,7,63,67};
    int row8[8]={99,65,4,28,6,16,70,92};
    int row9[9]={41,41,26,56,83,40,80,70,33};
    int row10[10]={41,48,72,33,47,32,37,16,94,29};
    int row11[11]={53,71,44,65,25,43,91,52,97,51,14};
    int row12[12]={70,11,33,28,77,73,17,78,39,68,17,57};
    int row13[13]={91,71,52,38,17,14,91,43,58,50,27,29,48};
    int row14[14]={63,66,4,68,89,53,67,30,73,16,69,87,40,31};
    int row15[15]={4,62,98,27,23,9,70,98,73,93,38,53,60,4,23};

    ConsolidateBottomThreeRows(row13, row14, row15);
    ConsolidateBottomThreeRows(row11, row12, row13);
    ConsolidateBottomThreeRows(row9, row10, row11);
    ConsolidateBottomThreeRows(row7, row8, row9);
    ConsolidateBottomThreeRows(row5, row6, row7);
    ConsolidateBottomThreeRows(row3, row4, row5);
    ConsolidateBottomThreeRows(row1, row2, row3);

    cout<<row1[0];
}

非常感谢任何帮助。谢谢!

Answer 1

数组没有size() 方法!您需要将大小作为单独的参数传递给函数，或者使用容器(例如 std::vector)。