c++ - 如果 unique_lock 管理的互斥量被销毁怎么办？

Question

void Fn() {
  std::mutex* mutex = new std::mutex;
  std::unique_lock<std::mutex> lock(*mutex);
  delete mutex;
}

上面的代码片段中是否有未定义的行为？

Answer 1

甚至在锁的析构函数运行之前，您就处于 UB 领域。 §30.4.1.2.1 [thread.mutex.class]/p5:

The behavior of a program is undefined if it destroys a mutex object owned by any thread or a thread terminates while owning a mutex object.