javascript - 检查所有复选框，如果它们具有相同的值

Question

这是我的html代码:

 <ul>
   <li>
  <input name="Services[]" class="form-control" value="Canbeprivatized" id="Canbeprivatized" type="checkbox"><label for="Canbeprivatized">Can be privatized </label>
   </li>
   <li>
   <input name="Services[]" class="form-control" value="Englishspoken" id="Englishspoken" type="checkbox"><label for="Englishspoken">English spoken </label>
   </li>
   <li>
   <input name="Services[]" class="form-control" value="Françaisparle" id="Françaisparle" type="checkbox"><label for="Françaisparle">Français parlé </label>
   </li>
   <li>
   <input name="Services[]" class="form-control" value="Petsallowed" id="Petsallowed" type="checkbox"><label for="Petsallowed">Pets allowed </label>
   </li>
   <li>
   <input name="Services[]" class="form-control" value="Piscine" id="Piscine" type="checkbox"><label for="Piscine">Piscine </label>
   </li></ul>

jQuery 代码:

var tab = new Array();
tab = data.services.split(",");// data is values of Checkboxes inserted in create form, so now i need to show it because this is edit form

我的问题是如何选中所有值等于选项卡中值的复选框。需要你的帮助，谢谢

Answer 1

如下操作，在tab上迭代:

for (i = 0; i < tab.length; i++)
  $('input[type=checkbox][value=' + tab[i] + ']').prop("checked", true);