java - 无响应的 HTTP 处理程序

Question

我正在编写一个测试 HTTPHandler，并连接到我使用此测试代码创建的服务器。

public static void main( String[] args ) throws Exception {
        String param = URLEncoder.encode( "raghu", Constants.ENCODING_CHARSET );
        String uri = "http://127.0.0.1:" + Constants.PORT_NUMBER + "/test" + "?" + "welcome=" + param;
        URL url = new URL( uri );
        HttpURLConnection conn = ( HttpURLConnection ) url.openConnection();
        conn.setRequestMethod( "GET" );
        conn.setRequestProperty( "Accept", "application/xml" );
        conn.setDoOutput( true );
        conn.setReadTimeout( 5000 );


                InputStream responseCode = conn.getInputStream();
                System.out.println();
                String toString = convertInputStreamToString( responseCode );
                System.out.println( "response-->" + toString );

        conn.disconnect();
    }

    private static String convertInputStreamToString( InputStream inputStream ) throws IOException {
        StringBuffer out = new StringBuffer();
        byte[] b = new byte[4096];
        for ( int i; ( i = inputStream.read( b ) ) != -1; ) {
            out.append( new String( b, 0, i ) );
        }
        return out.toString();
    }

我的处理程序代码是，

public class TestServiceAPI extends BaseServiceAPI {

    @Override
    public void handle( HttpExchange arg0 ) throws IOException {
        Map<String, Object> params = getParams( arg0 );
        System.out.println( "Inside test service---> " + params.get( "welcome" ) );
    }

}

那么是否必须从处理程序发送一些响应？我的代码在 InputStream responseCode = conn.getInputStream(); 处停止，因为这是我知道的唯一触发方式。请告诉我我的做法是否正确，或者是否有其他方式向服务器发出请求。

谢谢。

Answer 1

我的错..答案真的很简单。

我只是将其添加到我的处理程序代码中:

request.sendResponseHeaders( 200, 0 );