c++ - 为什么这会进入无限循环？

Question

好的，所以我正在尝试创建一个包含文件夹、子文件夹及其文件的列表，但现在它不打印任何内容，而且似乎进入了无限循环。知道为什么吗？

 //infinate loop start
        for(int j = 0; j < (int) dirs[i].folders.size(); j++){
            dirs.push_back(Directory(dirs[i].folders[j]));

            getfiles(dirs[i].dir,dirs[i].files);
            getfolders(dirs[i].dir,dirs[i].folders);
        }
        //infinate loop end

这是完整的来源:

#include <sys/types.h>
#include <sys/stat.h>
#include <dirent.h>
#include <errno.h>
#include <vector>
#include <string>
#include <iostream>

using namespace std;

struct Directory{
  public:
        int indent;
        vector<string> files;
        vector<string> folders;
        string dir;
        Directory(string mydir){ dir = mydir;}
};

int getfolders (string dir, vector<string> &folders)
{
    DIR *dp;
    struct stat st;
    struct dirent *dirp;
    if((dp  = opendir(dir.c_str())) == NULL) {
        cout << "Error(" << errno << ") opening " << dir << endl;
        return errno;
    }

    while ((dirp = readdir(dp)) != NULL) {
        stat(dirp->d_name, &st);

        if(S_ISDIR(st.st_mode)){
            if(dirp->d_name[0] != '.')
                folders.push_back(string(dirp->d_name));
        }
    }
    closedir(dp);
    return 0;
}

/*function... might want it in some class?*/
int getfiles (string dir, vector<string> &files)
{

    DIR *dp;
    struct stat st;
    struct dirent *dirp;
    if((dp  = opendir(dir.c_str())) == NULL) {
        cout << "Error(" << errno << ") opening " << dir << endl;
        return errno;
    }

    while ((dirp = readdir(dp)) != NULL) {
        stat(dirp->d_name, &st);

        if(!S_ISDIR(st.st_mode)){
            files.push_back(string(dirp->d_name));
        }
    }
    closedir(dp);
    return 0;
}

int main()
{
    struct Directory root = Directory(".");


    vector<string> display = vector<string>();

    cout << "hello\n";

    getfiles(root.dir,root.files);
    getfolders(root.dir,root.folders);

    cout << "hello\n";

    vector<Directory> dirs = vector<Directory>();

    for(int i = 0; i < (int) root.folders.size(); i++){
        dirs.push_back(Directory(root.folders[i]));

       getfiles(dirs[i].dir,dirs[i].files);
        getfolders(dirs[i].dir,dirs[i].folders);


        //infinate loop start
        for(int j = 0; j < (int) dirs[i].folders.size(); j++){
            dirs.push_back(Directory(dirs[i].folders[j]));

            getfiles(dirs[i].dir,dirs[i].files);
            getfolders(dirs[i].dir,dirs[i].folders);
        }
        //infinate loop end
    }

    cout << "hello\n";

    for (int i = 0; i < (int) root.folders.size();i++) {
        cout << root.folders[i] << endl;
        for(int j = 0; j < (int) dirs[i].folders.size(); j++){
            cout << dirs[i].folders[j] << endl;
        }
    }
    return 0;
}

Answer 1

for (int i = 0; i < (int) root.folders.size();i++) {
    cout << root.folders[i] << endl;
    for(int j = 0; j < (int) dirs[i].folders.size(); i++){
        cout << dirs[i].folders[j] << endl;
    }
}

我不太了解C++，但是第二个i++不应该是j++吗？否则 j 将始终为零，从而满足小于 dirs[i].folders.size() 的条件，因此循环永远不会结束。