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Question

我试图编译下面的代码，但我总是得到提到的错误:

#include <stdio.h>
#include <stdlib.h>

typedef struct
{
    char* Name;
    char* Branch;
} st_employee;

st_employee details[3] =
{
    [0].Name = "XXX",
    [0].Branch = "YYY",
    [1].Name = "ZZZ",
    [1].Branch = "PPP",
    [2].Name = "III",
    [2].Branch = "LLLL"
};

int main()
{
    printf("Hello world!");
    return 0;
}

编译:

c++ -x c -std=c11  -O2 -Wall -Wextra -pedantic -pthread -pedantic-errors test.cpp -lm  -latomic  -Wmissing-field-initializers

错误:

test.cpp:44:5: warning: missing initializer for field 'Branch' of 'st_employee' [-Wmissing-field-initializers]
     [1].Name = "Chennai",
     ^
test.cpp:22:11: note: 'Branch' declared here
     char* Branch;
           ^
test.cpp:45:5: warning: missing initializer for field 'Branch' of 'st_employee' [-Wmissing-field-initializers]
     [2].Name = "Chennai"
     ^
test.cpp:22:11: note: 'Branch' declared here
     char* Branch;
           ^
test.cpp:46:1: warning: missing initializer for field 'Branch' of 'st_employee' [-Wmissing-field-initializers]
 };
 ^
test.cpp:22:11: note: 'Branch' declared here
     char* Branch;
           ^

如何修复错误？

Answer 1

您链接的代码是有效的 C11，而不是 C++11。由于 C 和 C++ 是完全不同的语言，因此不会使用 C++ 编译器进行编译。

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