java - 两个日历时间之间的差异。多一小时出结果

Question

我的日历中有 2 次。

    Calendar orarioP1 = new GregorianCalendar(2014, 3, 28, 8, 30, 00);
    Calendar orarioA1 = new GregorianCalendar(2014, 3, 28, 12, 35, 06);  

我实现了这个函数来获取时差，但它返回了+1小时的时差。
我需要返回正确的差异 4:05:06 但现在它返回我 5:05:06。谁能帮我吗？

public String getTimeDiff() {

    SimpleDateFormat sdf = new SimpleDateFormat("h:mm:ss");
    long milliSec1 = orarioP1.getTimeInMillis();
    long milliSec2 = orarioA1.getTimeInMillis();

    long timeDifInMilliSec;
    if(milliSec1 >= milliSec2) {
        timeDifInMilliSec = milliSec1 - milliSec2;
    } else {
        timeDifInMilliSec = milliSec2 - milliSec1;
    }

    long timeDifSeconds = timeDifInMilliSec / 1000;
    long timeDifMinutes = timeDifInMilliSec / (60 * 1000);
    long timeDifHours = timeDifInMilliSec / (60 * 60 * 1000);
    long timeDifDays = timeDifInMilliSec / (24 * 60 * 60 * 1000);

    Date date = new Date(timeDifSeconds);
    String difference = sdf.format(date);

    return difference;
}

Answer 1

尝试这样的事情

    Calendar orarioP1 = new GregorianCalendar(2014, 3, 28, 8, 30, 00);
    orarioP1.setTimeZone(TimeZone.getTimeZone("GMT"));
    Calendar orarioA1 = new GregorianCalendar(2014, 3, 28, 12, 35, 06);
    orarioA1.setTimeZone(TimeZone.getTimeZone("GMT"));
    System.out.println("Difference In Hours : "
       +(orarioA1.get(Calendar.HOUR_OF_DAY)-orarioP1.get(Calendar.HOUR_OF_DAY)));
    System.out.println("Difference In Minutes : "
        +(orarioA1.get(Calendar.MINUTE)-orarioP1.get(Calendar.MINUTE)));
    System.out.println("Difference In Seconds : "
        +(orarioA1.get(Calendar.SECOND)-orarioP1.get(Calendar.SECOND)));
    System.out.println("Difference In MiliSeconds : "
       +(orarioA1.get(Calendar.MILLISECOND)-orarioP1.get(Calendar.MILLISECOND)));