java - 正则表达式在 csv 字符串中查找值

Question

源字符串:

1,4,test,v,4t,10,20,more  

需要使用正则表达式来查看该字符串是否包含这些值中的任何一个。所以问题是:

Does the source string have 1 in it?  Yes
Does the source string have 10 in it? Yes
Does the source string have v in it? Yes

Does the source string have 01 in it? No
Does the source string have va in it? No
Does the source string have test,v in it?  (invalid input, so don't have to worry about it)

附注核心语言是Java。

<小时/>

回应:“您不使用专用正则表达式解析器的原因是什么？”答案:嗯，我正在使用 Java，因此将使用 java.util.regex 类。据我所知，正则表达式在很大程度上是语言中立的，所以我不完全理解你的目的，你能解释一下吗？

<小时/>

回应:“为什么需要正则表达式？您可以在循环中使用单独的 contains() 调用，这会更容易维护和理解。”回答:我的印象是，如果注释正确，编写良好的正则表达式将执行得更快并且更易于阅读。我是不是搞错了？

Answer 1

简单高效:)

public class App {

    static String answer(int index) {
        return index < 0 ? "No" : "Yes";
    }

    public static void main(String[] args) {
        String line = "1,4,test,v,4t,10,20,more";

        String[] arr = line.split(",");

        Arrays.sort(arr);

        System.out.println(String.format("Does the source string have 1 in it? %s", answer(Arrays.binarySearch(arr, "1"))));
        System.out.println(String.format("Does the source string have 10 in it? %s", answer(Arrays.binarySearch(arr, "10"))));
        System.out.println(String.format("Does the source string have v in it? %s", answer(Arrays.binarySearch(arr, "v"))));
        System.out.println(String.format("Does the source string have 01 in it? %s", answer(Arrays.binarySearch(arr, "01"))));
        System.out.println(String.format("Does the source string have va in it? %s", answer(Arrays.binarySearch(arr, "va"))));
        System.out.println(String.format("Does the source string have test,v in it? %s", answer(Arrays.binarySearch(arr, "test,v"))));

    }
}

输出:

Does the source string have 1 in it? Yes
Does the source string have 10 in it? Yes
Does the source string have v in it? Yes
Does the source string have 01 in it? No
Does the source string have va in it? No
Does the source string have test,v in it? No