c++ - c++中菜单和子菜单的优化

Question

我创建了一个包含四个选项的菜单，当您选择其中一个选项时，系统会将您重定向到另一个子菜单，例如，其中有两个选项，之后程序将执行它们必须执行的操作。我成功地做到了这一点，但我的问题是我想对此进行优化，以便用户插入的所有可能性都将是一个相同的函数 Menu_select() 以便正确编码。例如，如果用户选择选项 2，然后选择选项 1，所有这些都将在 Menu_select() 下进行管理，而不是在每个子菜单中如果选择 (x) do x 并且如果选择 (y) do ( y)。总而言之，我想将用户可以选择的所有选项集中在同一个功能下。

这是我的代码:

int Shop::Menu_select(int choose)
{
    switch (choose)
    {
    case 1:
        break;
    case 2:
        Menu_Video();
        break;
    case 3:
        break;
    case 4:
        exit(EXIT_FAILURE);
        break;
    default:
        break;
    }
}
void Shop::Menu()
{
    int choose = 0;
    cout << "Rony Dvd Rental Shop !" << endl;
    cout << "1.Customer" << endl;
    cout << "2.Dvd" << endl;
    cout << "3.Rental" << endl;
    cout << "4.Exit" << endl;

    cout << endl << "Choose an option: ";
    cin >> choose;

    Menu_select(choose);
}
void Shop::Menu_Video()
{
    int choose = 0;

    system("cls");
    cout << "1.Add Dvd to the store " << endl;
    cout << "2.Delete Dvd from the store " << endl;

    cout << endl << "Choose an option: "; 
    cin >> choose;

    if (choose == 1)
    {
        system("cls");
        cout << "You want to add Dvd to the store" << endl;
    }
    else
    {
        system("cls");
        cout << "You want to delete Dvd from the store" << endl;
    }


}

谢谢!

Answer 1

你可以按照下面的例子进行优化

#include <iostream>
#include <string>

using namespace std;

int menu(string mArray[],int menuLength){
    int choosen = 0;
    for (int i=0;i<menuLength;i++)
      cout << mArray[i] << endl;
    cout << "Enter your choice -->" ;
    cin >> choosen;
   return choosen;
}

void menu_select(int select){
   switch(select){
     case 1:
       // for menu
       cout << "menu opt-1" << endl;
       break;
     case 2:
       cout << "menu opt-2" << endl;
       break;
     case 3:
       cout << "menu opt-3" << endl;
       break;
     case 4:
       cout << "menu opt-4" << endl;
       break;
     case 5:
     // for sub-menu
       cout << "sub-menu opt-1" << endl;
       break;
     case 6:
      // for sub-menu
        cout << "sub-menu opt-2" << endl;
        break;
     }
 }

int main(){

   string menu1[] = {"1.Option1","2.Option2","3.Option3","4.Option4"};
   string menu2[] = {"1.Option-1","2.Option-2"};

   int ch1=0,ch2=0;
   ch1 = menu(menu1,4);
   cout << "You entered:" << ch1 << endl;

   menu_select(ch1);
   ch2=menu(menu2,2);
   //sub-menu with options
   cout << "You entered:" << ch2 << endl;

   //check ch2 not zero
   menu_select(ch2+4); // if main menu has four options
}