java - 从 txt 文件名(一个单词)和(整数)中读取输入。将包含年龄和姓名的列表写入输出文件

Question

完成后输出应该是:

15    Michael
16    Jessica
20    Christopher
19    Ashley 
etc.

我对此不太擅长，并且希望获得有关如何让 int 和字符串逐行打印的任何输入。我避免使用数组方法，因为我总是在数组方面遇到困难。谁能告诉我我是否走在正确的轨道上，以及如何正确解析或类型转换整数，以便可以将它们打印在输出文件的一行上？我已经为此工作了几天，非常感谢任何帮助!这是我到目前为止所拥有的。

import java.io.PrintWriter;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.FileNotFoundException;
import java.util.Scanner;

public class NameAgeReverse
{
  public static void main (String[] args)
  {
    System.out.println("Programmed by J");
    String InputFileName;
    String OutputFileName;

    Scanner keyboard = new Scanner(System.in);
    System.out.print("Input file: ");
    InputFileName = keyboard.nextLine();

    System.out.print("Output file:  ");
    OutputFileName = keyboard.nextLine();    


    Scanner inputStream = null;
    PrintWriter outputStream = null;
        try
        {
       inputStream = new Scanner(new FileInputStream("nameAge.txt"));
           outputStream =new PrintWriter(new FileOutputStream("ageName.txt"));

    }
        catch(FileNotFoundException e)
        {
           System.out.println("File nameAge.txt was not found");
           System.out.println("or could not be opened.");
           System.exit(0);
        }
       int x = 0;
       String text = null;
       String line = null;

       while(inputStream.hasNextLine())
       {
         text = inputStream.nextLine();
         x = Integer.parseInt(text);
         outputStream.println(x + "\t" + text);
       }
         inputStream.close();
         outputStream.close();          

    }

    }

这是我的错误消息:

Exception in thread "main" java.lang.NumberFormatException: For input string: "Michael"
    at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    at java.lang.Integer.parseInt(Integer.java:492)
    at java.lang.Integer.parseInt(Integer.java:527)
    at NameAgeReverse.main(NameAgeReverse.java:52)

Answer 1

text = inputStream.nextLine(); 将读取包含姓名和年龄的整行文本。假设输入文件中每一行的格式都是年龄名称，您可以执行以下操作将每一行文本解析为所需的值。请注意，这不能与您的其余代码一起立即使用。只是一个指针:

text = inputStream.nextLine().split(" "); // split each line on space
age = Integer.parseInt(text[0]); // age is the first string
name = text[1];