c++ 和 fastcgi - 上游在读取来自上游的响应 header 时过早关闭 FastCGI stdout

Question

我正在使用 nginx、factcgi 和 spawn-fcgi 并试图让它工作。

我按如下方式启动 spawn-fcgi:

g++ rtbTimeSeries.cpp -o forecast.fcgi -I/home/ubuntu/cpp/boost_1_52_0/ -I/home/ubuntu/cpp/NR_C301/ -lfcgi++ -lfcgi
spawn-fcgi -a 127.0.0.1 -p 8010 -n forecast.fcgi

当我去

http://127.0.0.1:83/forecast.fcgi 

我收到 502 错误

当我从命令行查看 spawn-fcgi 的输出时，我看到了正确的输出...请参阅帖子的最底部:

在 nginx 日志中我得到这个:

2013/02/21 19:42:39 [error] 16342#0: *39 upstream closed prematurely FastCGI stdout while reading response header from upstream, client: 127.0.0.1, server: 127.0.0.1, request: "GET /forecast.fcgi HTTP/1.1", upstream: "fastcgi://127.0.0.1:8010", host: "127.0.0.1:83"

这是我的 C++ 代码:

int main() {
    FCGX_Init();
    while(FCGI_Accept() >= 0){
        printf("Content-type: text/html\r\n"
                       "\r\n"

                       "<title>FastCGI Hello!</title>"
                       "<h1>FastCGI Hello!</h1>"
                       "Request number %d running on host <i>%s</i>\n",
                        ++count, getenv("SERVER_NAME"));
    }
    return 0;
}

这是我的 nginx.conf 部分:

server {
              listen 83;
              server_name 127.0.0.1;

             location / {
          fastcgi_pass   127.0.0.1:8010;

          fastcgi_param  GATEWAY_INTERFACE  CGI/1.1;
          fastcgi_param  SERVER_SOFTWARE    nginx;
          fastcgi_param  QUERY_STRING       $query_string;
          fastcgi_param  REQUEST_METHOD     $request_method;
          fastcgi_param  CONTENT_TYPE       $content_type;
          fastcgi_param  CONTENT_LENGTH     $content_length;
          fastcgi_param  SCRIPT_FILENAME    $document_root$fastcgi_script_name;
          fastcgi_param  SCRIPT_NAME        $fastcgi_script_name;
          fastcgi_param  REQUEST_URI        $request_uri;
          fastcgi_param  DOCUMENT_URI       $document_uri;
          fastcgi_param  DOCUMENT_ROOT      $document_root;
          fastcgi_param  SERVER_PROTOCOL    $server_protocol;
          fastcgi_param  REMOTE_ADDR        $remote_addr;
          fastcgi_param  REMOTE_PORT        $remote_port;
          fastcgi_param  SERVER_ADDR        $server_addr;
          fastcgi_param  SERVER_PORT        $server_port;
          fastcgi_param  SERVER_NAME        $server_name;
        }


    }

下面是我在浏览器中点击 url 时控制台的输出。

spawn-fcgi -a 127.0.0.1 -p 8010 -n forecast.fcgi
Content-Type: text/plain

Hello world in C
Content-type: text/html

<title>FastCGI Hello!</title><h1>FastCGI Hello!</h1>Request number 1 running on host <i>127.0.0.1</i>
Content-Type: text/plain

Hello world in C
Content-type: text/html

<title>FastCGI Hello!</title><h1>FastCGI Hello!</h1>Request number 2 running on host <i>127.0.0.1</i>
Content-Type: text/plain

Hello world in C
Content-type: text/html

<title>FastCGI Hello!</title><h1>FastCGI Hello!</h1>Request number 3 running on host <i>127.0.0.1</i>
Content-Type: text/plain

Hello world in C
Content-type: text/html

<title>FastCGI Hello!</title><h1>FastCGI Hello!</h1>Request number 4 running on host <i>127.0.0.1</i>
Content-Type: text/plain

Hello world in C
Content-type: text/html

<title>FastCGI Hello!</title><h1>FastCGI Hello!</h1>Request number 5 running on host <i>127.0.0.1</i>

Answer 1

是否需要#include "fcgi_stdio.h"？

如果我从头开始编写应用程序，我会显式使用 FCGI_printf 而不是依赖 fcgi_stdio.h 中的#define 魔法。