java GUI 多线程与套接字

Question

我正在尝试制作一个从 TCP 套接字获取数据的 GUI 程序。问题是当我设置套接字然后启动它时，GUI 程序卡住。我想添加一个通过使用单击事件来停止线程的函数。

据我所知我必须使用 EDT，我尝试过但不起作用。有谁可以帮助我吗？

这是我的代码。

1. 主要内容

   public class ImageSplit {  
   static ImageViewerFrame program;
   public static void main(String[] args) throws IOException {  
   JPanel[] displayArray = new JPanel[100];   
   program = new ImageViewerFrame();
   
   EventQueue.invokeLater(new Runnable(){
   
       @Override
       public void run() {
           // TODO Auto-generated method stub
           program.setVisible(true);
       }
   
   });
   } 
   

2. 框架

   void createMouseMenu() {
   final PopupMenu menu = new PopupMenu();
   MenuItem grid = new MenuItem("Grid");
   MenuItem start = new MenuItem("Start");
   MenuItem stop = new MenuItem("Stop");
   menu.add(grid);
   menu.add(start);
   menu.add(stop);
   add(menu);
   
   mouseMenuHandler mousemenu = new mouseMenuHandler();
   
   grid.addActionListener(mousemenu);
   start.addActionListener(mousemenu);
   stop.addActionListener(mousemenu);
   
   addMouseListener(new MouseAdapter() {
       public void mousePressed(MouseEvent e) {
           if (e.getModifiers() == InputEvent.BUTTON3_MASK)
               menu.show(e.getComponent(), e.getX(), e.getY());
       }
   });
      }
   class mouseMenuHandler implements ActionListener {
   getInfo info;
   
   public void actionPerformed(ActionEvent e) {// open grid setting
       if (e.getActionCommand().equals("Grid")) {
           gridSettingUI = new GridSetting(img);
           gridSettingUI.setVisible(true);
       } else if (e.getActionCommand().equals("Start")) {
           try {
               info = new getInfo(40000);//open socket
               info.run();
           } catch (IOException e1) {
               // TODO Auto-generated catch block
               e1.printStackTrace();
           }
       } else if (e.getActionCommand().equals("Stop")) {
           System.out.println("stop");
           info.stop();
       }
   }
   }
   

3. socket接收

   import java.io.BufferedReader;
   import java.io.IOException;
   import java.io.InputStream;
   import java.io.InputStreamReader;
   import java.net.ServerSocket;
   import java.net.Socket;
   
   
   
   public class getInfo implements Runnable{
   ServerSocket serverSocket;
   private boolean stopped=false;
   
   public getInfo(int port_num) throws IOException{
   serverSocket = new ServerSocket(port_num);
   }
   @Override
   public void run() {
   // TODO Auto-generated method stub
   while(!stopped){
   try {
   Socket socket = serverSocket.accept();
   System.out.println(socket.getInetAddress()+ "connected");
   
   InputStream is = socket.getInputStream();
   InputStreamReader isr = new InputStreamReader(is);
   BufferedReader br = new BufferedReader(isr);
   if(br.ready())
   {
   String line = br.readLine();
   System.out.println(line+"\n");
   }
   } catch (IOException e) {
   // TODO Auto-generated catch block
           e.printStackTrace();
       }
   }
   }
   
   public void stop(){
   stopped = true;        
   }
   

}

Answer 1

info = new getInfo(40000);//open socket
info.run();

在上面的行中，您没有启动一个线程，相反，您只是在同一线程中执行run()方法(就像任何其他方法调用一样)。

从Thread扩展，然后调用info.start()。

请参阅:Java 谜题:陷阱、陷阱和极端情况，作者:Joshua Bloch 和 Neal Gafter，Puzzle #76 .